Answer:
100.2g of CuI₂ you must add
Explanation:
Molality, m, is defined as the ratio between moles of solute and kg of solvent.
In the problem, you have a 0.694m of copper (II) iodide -CuI₂, molar mass: 317.35 g/mol-. That means there are 0.694 moles of CuI₂ per kg of water.
As you have 455g = 0.455kg of water -solvent-, moles of CuI₂ are:
0.455kg ₓ (0.694 moles CuI₂ / kg) = 0.316 moles of CuI₂
Using molar mass, grams of CuI₂ in the solution are:
0.316moles CuI₂ ₓ (317.35g / mol) =
<h3>100.2g of CuI₂ you must add</h3>
<u>Answer:</u>
(a): The expression of equilibrium constant is ![K_{eq}=\frac{[NO]^2}{[N_2][O_2]}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BNO%5D%5E2%7D%7B%5BN_2%5D%5BO_2%5D%7D)
(b): The equation to solve the concentration of NO is ![[NO]=\sqrt{K_{eq}\times [N_2]\times [O_2]}](https://tex.z-dn.net/?f=%5BNO%5D%3D%5Csqrt%7BK_%7Beq%7D%5Ctimes%20%5BN_2%5D%5Ctimes%20%5BO_2%5D%7D)
(c): The concentration of NO is 0.0017 M.
<u>Explanation:</u>
The equilibrium constant is defined as the ratio of the concentration of products to the concentration of reactants raised to the power of the stoichiometric coefficient of each. It is represented by the term 
(a):
The given chemical equation follows:

The expression for equilbrium constant will be:
![K_{eq}=\frac{[NO]^2}{[N_2][O_2]}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BNO%5D%5E2%7D%7B%5BN_2%5D%5BO_2%5D%7D)
(b):
The equation to solve the concentration of NO follows:
......(1)
(c):
Given values:

![[N_2]_{eq}=0.166M](https://tex.z-dn.net/?f=%5BN_2%5D_%7Beq%7D%3D0.166M)
![[O_2]_{eq}=0.145M](https://tex.z-dn.net/?f=%5BO_2%5D_%7Beq%7D%3D0.145M)
Plugging values in equation 1, we get:
![[NO]=\sqrt{(1.2\times 10^{-4})\times 0.166\times 0.145}](https://tex.z-dn.net/?f=%5BNO%5D%3D%5Csqrt%7B%281.2%5Ctimes%2010%5E%7B-4%7D%29%5Ctimes%200.166%5Ctimes%200.145%7D)
![[NO]=\sqrt{2.88\times 10^{-6}}](https://tex.z-dn.net/?f=%5BNO%5D%3D%5Csqrt%7B2.88%5Ctimes%2010%5E%7B-6%7D%7D)
![[NO]=0.0017 M](https://tex.z-dn.net/?f=%5BNO%5D%3D0.0017%20M)
Hence, the concentration of NO is 0.0017 M.
Answer:When the Moon is between the Earth and the Sun, the bright side of the Moon is facing away from the Earth, and we have a New Moon.
Explanation:
Answer:
One can of cola contain 0.16 kcal of carbohydrates.
Explanation:
Given data:
mass of cola can = 40 g
kilocalories of carbohydrates = ?
Solution:
we know that there are 4 cal of carbohydrates per gram.
40 g × 4 cal/g = 160 cal
Now we will convert calories into kilocalories. There are 1000 calories in one kilocalories so,
160/1000 = 0.16 kcal
so, one can of cola contain 0.16 kcal of carbohydrates.