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3 years ago

There are two main ways that minerals are classified. Which identifies those two main ways?

2 answers:

6 0

A mineral is a naturally occurring inorganic crystalline solid that are the building blocks of rocks. Rocks are made up of different minerals. The most appropriate answer is c. crystal structure and economic value. Some minerals are classified as semiprecious or precious because of their economic value. Minerals such as diamonds and emeralds are precious and are very valuable.

prohojiy [21]3 years ago

6 0

Minerals are classified based on their physio chemical properties

The chemical properties are related to crystal structure

physical appearance of mineral defines its cost

so the minerals are classified based on crystal structure and economic value

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Henok is observing the reaction rate of a chemical reaction. He then adds a catalyst to the reaction.

tia_tia [17]

A catalyst will ALWAYS increase the reaction rate so C

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2 years ago

Chem. Assignment I need help...with answers 1-6 thanks

Anna11 [10]

Answer:

1. an educated guess

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3 years ago

What happens when air moves from an area of high pressure to an area of low pressure?

tino4ka555 [31]

Answer: The answer is D. wind is created. :)

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3 years ago

Read 2 more answers

Write in scientific form 0.00580 → 3000 → 0.000908 → 200. →

vagabundo [1.1K]

Answer:

Explanation:

0.00580=5.8*10^-3

3000=3.0*10^3

0.000908=9.08*10^-4

200.=2.0*10^2

6 0

2 years ago

Write the balanced standard combustion reaction for the c5h7on3s2

AlexFokin [52]

Answer:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Explanation:

When C5H7ON3S2 under go Combustion, the following are obtained as illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

Now, let us balance the equation. This is illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

There are 3 atoms of N on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of C5H7ON3S2 and 6 in front of N2 as shown below:

4C5H7ON3S2 + O2 —> CO2 + H2O + 6N2 + S2

There are 20 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 20 in front of CO2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + H2O + 6N2 + S2

There are 28 atoms on H on the left side and 2 atoms on the right side. It can be balance by putting 14 in front of H2O as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + S2

There are 8 atoms of S on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of S2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, there are a total of 54 atoms of O on the right side and 6 atoms on the left side

It can be balance by putting 25 in front of O2 as shown below:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, we can see that the equation is balanced.

4 0

2 years ago