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andre [41]
3 years ago
10

What happens at the cathode in an electrolytic cell? (Answer is reduction)

Chemistry
2 answers:
melisa1 [442]3 years ago
7 0

Answer:

At the cathode in an electrolytic cell, ions in the surrounding solution are reduced into atoms, which precipitate or plate out on to the solid cathode. The anode is where oxidation takes place, and the cathode is where reduction takes place.

Explanation:

Fantom [35]3 years ago
6 0

Answer:

<em>reduction</em>

Explanation:

<em>a p e x :)</em>

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Determine the volume of a 0.800 M K2Cr2O7 solution required to completely react with 4.24 g of Cu.
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<u>Answer:</u> The volume of solution required is 0.0275 L.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of copper = 4.24 g

Molar mass of copper = 63.55 g/mol

Putting values in above equation, we get:

\text{Moles of copper}=\frac{4.24g}{63.55g/mol}=0.067mol

The chemical equation for the reaction of potassium dichromate and copper follows:

K_2Cr_2O_7+3Cu+7H_2SO_4\rightarrow 3CuSO_4+Cr_2(SO_4)_3+K_2SO_4+7H_2O

By Stoichiometry of the reaction:

3 moles of copper reacts with 1 mole of potassium dichromate.

So, 0.067 moles of copper will react with = \frac{1}{3}\times 0.067=0.022mol of potassium dichromate

To calculate the volume of potassium dichromate, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

We are given:

Moles of potassium dichromate = 0.022 mol

Molarity of solution = 0.800 M

Putting values in above equation, we get:

0.08mol/L=\frac{0.022mol}{\text{Volume of solution}}\\\\\text{Volume of solution}=0.0275L

Hence, the volume of solution required is 0.0275 L.

6 0
3 years ago
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