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Ede4ka [16]
3 years ago
13

In golf, the lower the score, the better. Negative scores are best of all. Tom scores +2 on each of the first three holes at a n

ine-hole miniature golf course. His goal is a total of -12 or better after he has completed six holes. Write a two-step inequality equation to solve for h.
Mathematics
1 answer:
bazaltina [42]3 years ago
8 0

Answer:

Jusy give me that coins

Step-by-step explanation:

Idk the answer im dum jk i think it is 329

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What is the area of this trapezoid? Please help me
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192

Step-by-step explanation:

both triangles are 12 in and the square is 168

so 12+12+168= 192in

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Can sum1 help me w this plz
mel-nik [20]

Answer:  x = 1.28 or -1.28

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What is 2/3 divided by 10?
Dahasolnce [82]
2/3 x 1/10
= 2/30
= 1/15
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Given any two numbers, which is greater, the lowest common multiple of the numbers or the greatest common multiple?
tester [92]

After you've calculated a least common multiple, always check to be sure your answer can be divided evenly by both numbers. Find the LCM of these sets of numbers. Multiply each factor the greatest number of times it occurs in any of the numbers. 9 has two 3's, and 21 has one 7, so we multiply 3 two times, and 7 once.

4 0
3 years ago
Let R be the relation on the set of ordered pairs of positive integers such that ((a, b), (c, d)) ∈ R if and only if ad = bc. Ar
Veseljchak [2.6K]

Answer:

The given relation R is equivalence relation.

Step-by-step explanation:

Given that:

((a, b), (c, d))\in R

Where R is the relation on the set of ordered pairs of positive integers.

To prove, a relation R to be equivalence relation we need to prove that the relation is reflexive, symmetric and transitive.

1. First of all, let us check reflexive property:

Reflexive property means:

\forall a \in A \Rightarrow (a,a) \in R

Here we need to prove:

\forall (a, b) \in A \Rightarrow ((a,b), (a,b)) \in R

As per the given relation:

((a,b), (a,b) ) \Rightarrow ab =ab which is true.

\therefore R is reflexive.

2. Now, let us check symmetric property:

Symmetric property means:

\forall \{a,b\} \in A\ if\ (a,b) \in R \Rightarrow (b,a) \in R

Here we need to prove:

\forall {(a, b),(c,d)} \in A \ if\ ((a,b),(c,d)) \in R \Rightarrow ((c,d),(a,b)) \in R

As per the given relation:

((a,b),(c,d)) \in R means ad = bc

((c,d),(a,b)) \in R means cb = da\ or\ ad =bc

Hence true.

\therefore R is symmetric.

3. R to be transitive, we need to prove:

if ((a,b),(c,d)),((c,d),(e,f)) \in R \Rightarrow ((a,b),(e,f)) \in R

((a,b),(c,d)) \in R means ad = cb.... (1)

((c,d), (e,f)) \in R means fc = ed ...... (2)

To prove:

To be ((a,b), (e,f)) \in R we need to prove: fa = be

Multiply (1) with (2):

adcf = bcde\\\Rightarrow fa = be

So, R is transitive as well.

Hence proved that R is an equivalence relation.

8 0
3 years ago
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