Ask question

Ask question

All categories

Amiraneli [1.4K]

3 years ago

7

What are the basics of chemistry

1 answer:

Novay_Z [31]3 years ago

5 0

In studying chemistry, one should learn how to read the periodic table and periodic trends in the table.. Of course, you should also know the abbreviations of each element in it so that you can identify what element is in chemical structures. Memorizing and knowing it by heart is the best way. You should also study what we call chemical nomenclature which is naming combinations of elements. Elements when combined may form ionic compounds, bonds or acids. Knowing what element reacts with another will also be necessary that's why the concept of chemical reactions must be further studied.

You might be interested in

What is the mass of arsenic that is contained in a 50.0 g sample if the concentration is 5 ppm?

faltersainse [42]

<u>Answer:</u> The mass of arsenic found in the sample is 0.25 mg

<u>Explanation:</u>

ppm is the amount of solute (in milligrams) present in kilogram of a solvent. It is also known as parts-per million.

To calculate the ppm of oxygen in sea water, we use the equation:

$\text{ppm}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6$

Both the masses are in grams.

We are given:

Concentration of arsenic = 5 ppm

Mass of sample = 50 g

Putting values in above equation, we get:

$5=\frac{\text{Mass of arsenic}}{50g}\times 10^6\\\\\text{Mass of arsenic}=\frac{5\times 50}{10^6}=0.00025g=0.25mg$

<u>Conversion factor used:</u> 1 g = 1000 mg

Hence, the mass of arsenic found in the sample is 0.25 mg

5 0

3 years ago

I will give brainlyest<br> Explain why science is a continuous progression of study.

Likurg_2 [28]

It’s because new discoveries are made all the time sometimes what was considered right may be found out to be wrong

8 0

4 years ago

CH=C-CH=CH– CH = CH, what is the name of this molecule?

Kobotan [32]

Answer:

pent-3-ene-1-yne

Explanation:

1 2 3 4 5

CH ≡ C - CH = CH - CH3

IUPAC name : Pent-3-ene-1-yne

3 0

3 years ago

When sugar glucose, C6H12O6, is burned with air, carbon dioxide and water vapor are produced. Write the balanced equation and ca

Alex Ar [27]

6CO2 + 6H2O YOU JUST ADD THEM TOGETHER

3 0

3 years ago

The half-life of a radioactive isotope is the amount of time it takes for a quantity of that isotope to decay to one half of its

Sedaia [141]

Radio active decay reactions follow first order rate kinetics.

a) The half life and decay constant for radio active decay reactions are related by the equation:

$t_{\frac{1}{2}} =$ $\frac{ln 2}{k}$

$t_{\frac{1}{2}} = \frac{0.693}{k}$

Where k is the decay constant

b) Finding out the decay constant for the decay of C-14 isotope:

$Decay constant (k) = \frac{0.693}{t_{\frac{1}{2}}}$

$k = \frac{0.693}{5230 years}$

$k = 1.325 * 10^{-4} yr^{-1}$

c) Finding the age of the sample :

35 % of the radiocarbon is present currently.

The first order rate equation is,

$[A] = [A_{0}]e^{-kt}$

$\frac{[A]}{[A_{0}]} = e^{-kt}$

$\frac{35}{100} = e^{-(1.325 *10^{-4})t}$

$ln(0.35) = -(1.325 *10^{-4})(t)$

t = 7923 years

Therefore, age of the sample is 7923 years.

3 0

3 years ago