1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
arsen [322]
3 years ago
10

Hydrogenation reactions are used to add hydrogen across double bonds in hydrocarbons and other organic compounds. use average bo

nd energies to calculate δhrxn for the hydrogenation reaction.
Chemistry
1 answer:
Mamont248 [21]3 years ago
7 0
H2(g) +C2H4(g)→C2H6(g)
H-H +H2C =CH2→H3C-Ch3
2C -H bonds and one C-C bond are formed while enthalpy change (dH) of the reaction,
H-H: 432kJ/mol
C=C: 614kJ/mol
C-C: 413 kJ/mol
C-C: 347 kJ/mol
dH is equal to sum of the energies released during the formation of new bonds or negative sign, and sum of energies required to break old bonds or positive sign.
The bond which breaks energy is positive.
432+614 =1046kJ/mol
Formation of bond energy is negative
2(413) + 347 = 1173 kJ/mol
dH reaction is -1173 + 1046 =-127kJ/mol 
You might be interested in
Esters are generally pleasant smelling compounds<br>True<br>False​
Rzqust [24]

Answer:

True

Explanation:

Esters are generally pleasantly smelling compounds. In fact, the fragrance industry uses esters to produce perfume, as well as uses esters as an ingredient to produce synthetic flavours and cosmetics, all of which have unique and pleasant smells.

8 0
3 years ago
(4 points) The following lead compound for a pharmaceutical drug contains a rotatable bond. Using the principles of rigidificati
masya89 [10]

Answer:

Explanation:

The solution has been attached

3 0
2 years ago
Calculate the concentration of an aqueous solution of naoh that has a ph of 11.50
Reika [66]
NaOH is a strong base and complete dissociation into Na⁺ and OH⁻ ions. 
Therefore [NaOH] = [OH⁻]
To calculate the [OH⁻], we can first find the pOH as NaOH is a basic solution.
pH + pOH = 14
Since pH = 11.50
pOH = 14 - 11.50
pOH = 2.50
We can calculate [OH⁻] by knowing pOH 
pOH = -log[OH⁻]
[OH⁻] = antilog(-pOH)
[OH⁻] = 3.2 x 10⁻³ M
therefore [NaOH] = 3.2 x 10⁻³ M
7 0
2 years ago
Read 2 more answers
The density of solid Cr is 7.15 g/cm3. How many atoms are present per cubic centimeter of Cr?
Masja [62]
To calculate the number of atoms of Cr, we first find the number of moles per unit of cubic centimeter of Cr. Then, use avogadros number for the number of atoms. Calculations are as follows:

1 cm^3 (7.15 g/cm^3) (1 mol / 51.996 g Cr) = 0.14 mol Cr

0.14 mol Cr ( 6.022 x 10^23 atoms Cr / 1 mol Cr ) = 8.28 x 10^22 atoms Cr
8 0
3 years ago
Please please help me with this chemistry question over limiting reactants it’s due by midnight! I’ll mark you BRAINIEST!!!
OverLord2011 [107]

Answer: 1.5 moles

Explanation: one mole Zn uses 2 moles HCl.

1.5 moles Zn uses 3.0 mol HCl. Then Zn is a limiting reactant

And produces equal amount of H2.

4 0
3 years ago
Other questions:
  • What methods do scientists use to determine if a change was physical or chemical?
    15·1 answer
  • An aqueous potassium iodate (KIO3) solution is made by dissolving 553 grams of KIO3 in sufficient water so that the final volume
    8·2 answers
  • 1). What are 4 factors that can affect Reaction Rates?
    14·1 answer
  • Calculate the molarity of a solution containing 15.2 grams of NaCl dissolved in 2.5 L of solution.
    11·1 answer
  • Ca+HCI—&gt;CaCI2+H2, what is the reaction?
    7·2 answers
  • Which is not a layer found in the earth's mantle? A. Upper mantle B. asthenosphere C. lithosphere D.crust
    13·1 answer
  • A 1.00 g sample of n-hexane (C6H14) undergoes complete combustion with excess O2 in a bomb calorimeter. The temperature of the 1
    15·1 answer
  • HELP I REALLY NEED HELP​
    7·1 answer
  • What is the name of the compound below?
    13·1 answer
  • Graph the circle which is centered at (4,4)(4,4)left parenthesis, 4, comma, 4, right parenthesis and has a radius of 3 units.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!