Answer:
<h2>
f₀ = 158.12 Hertz</h2>
Explanation:
The fundamental frequency of the string f₀ is expressed as f₀ = V/4L where V is the speed experienced by the string.
where T is the tension in the string and 
is the density of the string
Given T = 600N and = 0.015 g/cm = 0.0015kg/m
The next is to get the length L of the string. Since the string is stretched and fixed at both ends, 200 cm apart, then the length of the string in metres is 2m.
L = 2m
Substituting the derived values into the formula f₀ = V/2L
f₀ = 632.46/2(2)
f₀ = 632.46/4
f₀ = 158.12 Hertz
Hence the fundamental frequency of the string is 158.12 Hertz
Answer:
The final speed of puck 1 is 0.739 m/s towards west and puck 2 is 2.02 m/s towards east .
Explanation:
Let us consider east as positive direction and west as negative direction .
Given
mass of puck 1 , 
mass of puck 2 , 
initial speed of puck 1 , 
initial speed of puck 2 , 
Final speed of puck 1 and puck 2 be 
respectively
Apply conservation of linear momentum
=>
=>
-----(A)
Since collision is perfectly elastic , coefficient restitution e=1
=>
------(B)
From equation (A) and (B)
and 
Thus the final speed of puck 1 is 0.739 m/s towards west and puck 2 is 2.02 m/s towards east .
Answer:
3×10^-12 C
Explanation:
The total of the three charges is ...
(-3 +8 +4)×10^-12 C = 9×10^-12 C
Assuming the charge is equally distributed between the balls when they are brought in contact, the charge on each ball will be ...
(9/3)×10^-12 C = 3×10^-12 C
<h3>Solution for the above question : -</h3>
Ohm's law states that :
the terms used are :
let's solve for electric current :
