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1 answer:
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Answer:
a
b
Explanation:
From the question we are told that
The wavelength of the light is
The distance of the slit separation is
Generally the condition for two slit interference is
Where m is the order which is given from the question as m = 2
=>
substituting values
Now on the second question
The distance of separation of the slit is
The intensity at the the angular position in part "a" is mathematically evaluated as
Where is mathematically evaluated as
substituting values
So the intensity is
Speed of car A is given as
now we need to convert it into SI units
1 miles = 1609 m
1 hour = 3600 s
now we have
now its distance from Bambi is given as
time taken by it to hit the Bambi
Now other car is moving at speed 50 mph
so its speed in SI unit will be
now its distance from Bambi is given as
as we know that 1 feet = 0.3048 m
now the time to hit the other car is
So Car B will hit the Bambi first
Answer:
The ball will drop 0.881 m by the time it reaches the catcher.
Explanation:
The position of the ball at time "t" is described by the position vector "r":
r = (x0 + v0x · t, y0 + v0y · t + 1/2 · g · t²)
Where:
x0 = initial horizontal position.
v0x = initial horizontal velocity.
t = time.
y0 = initial vertical position.
v0y = initial vertical velocity.
g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).
When the ball reaches the catcher, the position vector will be "r final" (see attached figure).
The x-component of the vector "r final", "rx final", will be 17.0 m. We have to find the y-component.
Using the equation of the x-component of the position vector, we can calculate the time it takes the ball to reach the catcher (notice that the frame of reference is located at the throwing point so that x0 and y0 = 0):
x = x0 + v0x · t
17.0 m = 0 m + 40.1 m/s · t
t = 17.0 m/ 40. 1 m/s = 0.424 s
With this time, we can calculate the y-component of the vector "r final", the drop of the ball:
y = y0 + v0y · t + 1/2 · g · t²
Initially, there is no vertical velocity, then, v0y = 0.
y = 1/2 · g · t²
y = -1/2 · 9.8 m/s² · (0.424 s)²
y = -0.881 m
The ball will drop 0.881 m by the time it reaches the catcher.
