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denis23 [38]
3 years ago
9

Calculate the mass in grams of 1.13 x 102 molecules of propane. The chemical formula for propane is C3H8.

Chemistry
1 answer:
g100num [7]3 years ago
3 0
Moles = (6.74*10^23)/(6.02*10^23) =1.119 moles

1.119*44.09=49.36g
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3- Fully folded proteins typically have polar side chains on their surfaces, where electrostatic attractions and hydrogen bonds
Elden [556K]

Answer:

Option C= A hydrogen bond formed between a polar side chain and a hydrophobic side chain.

Explanation:

All three given options a, b and d have common mechanism to accommodate the polar amino acid.

A= A hydrogen bond forms between two polar side chains.

B= A hydrogen bond from between a polar side chain and protein back bone.

D =  hydrogen bond form between polar side chains and a buried water molecules.

All these are use to accommodate the polar amino acid.

While option C is not used. which is:

A hydrogen bond formed between a polar side chain and a hydrophobic side chain.

5 0
3 years ago
How many hydrogen atoms are in 35.0 grams of hydrogen gas? How many hydrogen atoms are in 35.0 grams of hydrogen gas? 4.25 × 102
Ede4ka [16]

Answer: 2.12\times 10^{25} atoms of hydrogen are there in

35.0 grams of hydrogen gas.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{35.0g}{2g/mol}=17.5moles

1 mole of hydrogen (H_2) = 2\times 6.023\times 10^{23}=12.05\times 10^{23} atoms

17.5 mole of hydrogen (H_2) = \frac{12.05\times 10^{23}}{1}\times 17.5=2.12\times 10^{25} atoms

There are 2.12\times 10^{25} atoms of hydrogen are there in

35.0 grams of hydrogen gas.

8 0
3 years ago
A brick measures 25 cm by 12 cm by 13 cm. What is the volume of the brick in cm3? How many milliliters of water would this brick
hodyreva [135]
Volume is lxwxh so do 25x12x13
7 0
3 years ago
8.
Oksi-84 [34.3K]

Answer:

900 mg

Explanation:

4 0
3 years ago
Calculate the PH of a solution 0.030 MH2SO4
Zinaida [17]

Answer:

pH= 2- log3

Explanation:

H2SO4 + H2O -> HSO4^(-) + H30^(+)

0.03M ___ ___

___ 0.03M 0.03M

H30^(+) : C = 0.03M

pH= - log( [H3O^(+)] ) => pH= - log {3× 10^(-2)} => pH = 2 - log3

4 0
3 years ago
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