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<span>1.16 moles/liter
The equation for freezing point depression in an ideal solution is
ΔTF = KF * b * i
where
ΔTF = depression in freezing point, defined as TF (pure) ⒠TF (solution). So in this case ΔTF = 2.15
KF = cryoscopic constant of the solvent (given as 1.86 âc/m)
b = molality of solute
i = van 't Hoff factor (number of ions of solute produced per molecule of solute). For glucose, that will be 1.
Solving for b, we get
ΔTF = KF * b * i
ΔTF/KF = b * i
ΔTF/(KF*i) = b
And substuting known values.
ΔTF/(KF*i) = b
2.15âc/(1.86âc/m * 1) = b
2.15/(1.86 1/m) = b
1.155913978 m = b
So the molarity of the solution is 1.16 moles/liter to 3 significant figures.</span>
It is approximately 10 ^ -10
The balanced equation is:

Then proceed with the following equations.

The answer is

.
Answer:
200 Joules is the explosive energy in the inside the balloon. And that is
1 lb of TNT.
Explanation:

Volume of the balloon = V = 1 L = 
Pressure inside the balloon ,P= 200,000 Pa =
Explosive energy in the inside the balloon be E.
E = Pressure × Volume

1 lb of TNT = 
200 Joules =
1 lb of TNT
=
1 lb of TNT