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sineoko [7]
2 years ago
5

How many grams are there in 2.75E23 molecules of C2H6 (MM = 30 grams)?

Chemistry
1 answer:
skelet666 [1.2K]2 years ago
3 0

Answer:13.70 i think

Explanation:

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Toluene (C7H8) and nitric acid (HNO3) are used in the production of trinitrotoluene (TNT, C7H5N3O6), an explosive. C7H8 + HNO3 =
olga55 [171]
  The mass in grams  of nitric  acid that is required  to react  with 454g C7H8 is 932.72  grams

     calculation
find the  moles  of C7H8  used
moles = mass/molar mass

= 454 g/92  = 4.935  moles

balanced reacting  equation

C7H8  +3 HNO3  = C7H5N3O6  +3 H20
by  use of mole ratio between  C7H8  to  HNo3  which is  1:3  the moles of  HNO3  =4.935  x3 = 14.805  moles

mass of HNo3  =  moles  x molar mass
= 14.805  x 63  = 932.72  grams

part B

the  mass of  C7H5N3o6 = 2045.5 grams

calculate the moles of C7H8
= 829 g/92  g/mol  = 9.011  moles

by use of mole  ratio  between C7H8 to C7H5N3O6  which is  1:1  the moles of  C7H5N3O6  is also  = 9.011  moles

mass of  C7H5N3O6  is therefore  =  moles x molar mass

=9.011 x227  = 2045.5 grams
8 0
3 years ago
Consider the following reaction: NaHCO3 + HC2H3O2 → NaC2H3O2 + H2O + CO2 How many g of CO2 would be produced from the complete r
Alenkasestr [34]
<h2>1.25 g of CO_2 would be produced from the complete reaction of 25 mL of 0.833 mol/L HC_3H_3O_2 with excess NaHCO_3 </h2>

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}    

0.833M=\frac{\text{Moles of} HC_3H_3O_2\times 1000}{25ml}\\\\\text{Moles of} HC_3H_3O_2 =\frac{0.833mol/L\times 25}{1000}=0.0208mol

NaHCO_3+HC_2H_3O_2\rightarrow NaC_2H_3O_2+H_2O+CO_2

According to stoichiometry:

1 mole of HC_2H_3O_2 will give = 1 mole of CO_2

0.0208 moles of HC_2H_3O_2 will give =\frac{1}{1}\times 0.0208=0.0208 moles of CO_2

Mass of HC_2H_3O_2=moles\times {\text {molar mass}}=0.0208\times 60g/mol=1.25g

Thus 1.25 g of CO_2 would be produced from the complete reaction of 25 mL of 0.833 mol/L HC_3H_3O_2 with excess NaHCO_3

Learn more about molarity

https://brainly.in/question/13034158

#learnwithbrainly

5 0
3 years ago
Which of the following statements about decomposition reactions is true?
Andreyy89
C

Decomposition is of this form: A becomes B+C ... so after the reaction, the element A DECOMPOSES into two smaller elements, B and C.

Synthesis is the opposite: B+C becomes A AFTER THE REACTION.

Hope that helps :))
8 0
3 years ago
Read 2 more answers
What volume (in liters) of a solution contains 0.14 mol of KCl?
oksano4ka [1.4K]

Answer:

\boxed {\boxed {\sf 0.078 \ L }}

Explanation:

We are asked to find the volume of a solution given the moles of solute and molarity.

Molarity is a measure of concentration in moles per liter. It is calculated using the following formula:

molarity= \frac{moles \ of \ solute}{liters \ of \ solution}

We know there are 0.14 moles of potassium chloride (KCl), which is the solute. The molarity of the solution is 1.8 molar or 1.8 moles of potassium chloride per liter.

  • moles of solute = 0.14 mol KCl
  • molarity= 1.8 mol KCl/ L
  • liters of solution=x

Substitute these values/variables into the formula.

1.8 \ mol \ KCl/ L = \frac { 0.14 \ mol \ KCl}{x}

We are solving for x, so we must isolate the variable. First, cross multiply. Multiply the first numerator and second denominator, then the first denominator and second numerator.

\frac {1.8 \ mol \ KCl/L}{1} = \frac{0.14 \ mol \ KCl}{x}

1.8 \ mol \ KCl/ L *x = 1*0.14 \ mol \ KCl

1.8 \ mol \ KCl/ L *x = 0.14 \ mol \ KCl

Now x is being multiplied by 1.8 moles of potassium chloride per liter. The inverse operation of multiplication is division, so we divide both sides by 1.8 mol KCl/L.

\frac {1.8 \ mol \ KCl/ L *x}{1.8 \ mol \ KCl/L} = \frac{0.14 \ mol \ KCl}{1.8 \ mol \ KCl/L}

x= \frac{0.14 \ mol \ KCl}{1.8 \ mol \ KCl/L}

The units of moles of potassium chloride cancel.

x= \frac{0.14 }{1.8 L}

x=0.07777777778 \ L

The original measurements of moles and molarity have 2 significant figures, so our answer must have the same. For the number we found, that is the thousandth place. The 7 in the ten-thousandth place tells us to round the 7 up to a 8.

x \approx 0.078 \ L

There are approximately <u>0.078 liters of solution.</u>

5 0
3 years ago
In the front of the room, there is a bottle that contains a 32.00 g sample of sulfur. This is
Vera_Pavlovna [14]
6.02x10^23 atoms is the answer
8 0
3 years ago
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