How many grams are there in 2.75E23 molecules of C2H6 (MM = 30 grams)?
1 answer:
You might be interested in
<h2>1.25 g of 
would be produced from the complete reaction of 25 mL of 0.833 mol/L 
with excess 
</h2>
Explanation:
To calculate the number of moles for given molarity, we use the equation:
According to stoichiometry:
1 mole of will give = 1 mole of
0.0208 moles of will give =
of
Mass of
Thus 1.25 g of would be produced from the complete reaction of 25 mL of 0.833 mol/L
with excess
Learn more about molarity
https://brainly.in/question/13034158
#learnwithbrainly
Answer:
Explanation:
We are asked to find the volume of a solution given the moles of solute and molarity.
Molarity is a measure of concentration in moles per liter. It is calculated using the following formula:
We know there are 0.14 moles of potassium chloride (KCl), which is the solute. The molarity of the solution is 1.8 molar or 1.8 moles of potassium chloride per liter.
- moles of solute = 0.14 mol KCl
- molarity= 1.8 mol KCl/ L
- liters of solution=x
Substitute these values/variables into the formula.
We are solving for x, so we must isolate the variable. First, cross multiply. Multiply the first numerator and second denominator, then the first denominator and second numerator.
Now x is being multiplied by 1.8 moles of potassium chloride per liter. The inverse operation of multiplication is division, so we divide both sides by 1.8 mol KCl/L.
The units of moles of potassium chloride cancel.
The original measurements of moles and molarity have 2 significant figures, so our answer must have the same. For the number we found, that is the thousandth place. The 7 in the ten-thousandth place tells us to round the 7 up to a 8.
There are approximately <u>0.078 liters of solution.</u>