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2 years ago

5

How many grams are there in 2.75E23 molecules of C2H6 (MM = 30 grams)?

1 answer:

skelet666 [1.2K]2 years ago

3 0

Answer:13.70 i think

Explanation:

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What happens when an electron in its lowest energy level or ground state when it is by absorbs energy?

tester [92]

Explanation:

atom changes from a ground state to an excited state by taking on energy from its surroundings in a process called absorption. The electron absorbs the energy and jumps to a higher energy level. In the reverse process, emission, the electron returns to the ground state by releasing the extra energy it absorbed

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3 years ago

Can you help me please, I’ll mark brainliest.

GrogVix [38]

Answer:

i think A

Explanation:

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3 years ago

The vapor pressure of water at 65oC is 187.54 mmHg. What is the vapor pressure of a ethylene glycol (CH2(OH)CH2(OH)) solution ma

Pavlova-9 [17]

Answer:

173.83 mmHg is the vapor pressure of a ethylene glycol solution.

Explanation:

Vapor pressure of water at 65 °C= $p_o= 187.54 mmHg$

Vapor pressure of the solution at 65 °C= $p_s$

The relative lowering of vapor pressure of solution in which non volatile solute is dissolved is equal to mole fraction of solute in the solution.

Mass of ethylene glycol = 22.37 g

Mass of water in a solution = 82.21 g

Moles of water= $n_1=\frac{82.21 g}{18 g/mol}=4.5672 mol$

Moles of ethylene glycol= $n_2=\frac{22.37 g}{62.07 g/mol}=0.3603 mol$

$\frac{p_o-p_s}{p_o}=\frac{n_2}{n_1+n_2}$

$\frac{187.54 mmHg-p_s}{187.54 mmHg}=\frac{0.3603 mol}{0.3603 mol+4.5672 mol}$

$p_s=173.83 mmHg$

173.83 mmHg is the vapor pressure of a ethylene glycol solution.

6 0

3 years ago

a gas in a container with a fixed volume was originally at a pressure of 317kpa and a temperature of 154k. what is the new press

goldfiish [28.3K]

<h2>Hello!</h2>

The answer is: 4.77atm

<h2>Why?</h2>

Since there's a fixed volume, we can use the the Gay-Lussac's Law which stablish a relation between the pressure and the temperature:

$\frac{P}{T}=k$

<em>P</em> is the volume of the gas

<em>t</em> is the temperature of the gas

<em>k </em>is the proportionality constant

We also have the following equation:

$\frac{P1}{T1}=\frac{P2}{T2}$

Where:

$P2=\frac{P1*T2}{T1}=\frac{317kPa*235K}{154K}=483.73kPa$

We are asked to find the pressure in atm, so we must convert 483.73kPa to atm:

$1kPa=0.009869atm$

Then,

$483.733kPa*\frac{0.009869atm}{1kPa}=4.77atm$

Have a nice day!

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3 years ago

Predict the major product(s) formed when hexanoyl chloride is treated with c6h5co2na.

postnew [5]

Following reactions show the major product,

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3 years ago