H = v 0 y 2 2 g . h = v 0 y 2 2 g . This equation defines the maximum height of a projectile above its launch position and it depends only on the vertical component of the initial velocity.
<em>im confused hold on imma send you a link to the answer</em>Explanation:
The energy levels of the hydrogen atom are given by
where n is the level number. Let's use this formula to calculate the energy of the levels n=1 (ground state), n=5 and n=6:
- ground state:
- level n=5:
- level n=6:
Now that we have the energy for all the levels we are interested in, we can calculate the energy of the emitted photons.
a) In the first transition, the atom goes from n=6 to n=5. The energy of the emitted photon is equal to the energy difference between these two levels:
The energy of a photon is also equal to
where
h is the Planck constant
c is the speed of light
f is the photon frequency
is its wavelength
Re-arranging this relationship and using the photon's energy, we find its wavelength:
b) in the second transition, from n=5 to n=1, the energy of the emitted photon is equal to the difference in energy between the two levels:
Similarly to part a), the wavelength of the photon is given by:
Answer:
Gamma rays have the highest energies, the shortest wavelengths, and the highest frequencies. Radio waves, on the other hand, have the lowest energies, longest wavelengths, and lowest frequencies of any type of EM radiation.
Explanation:
Hope this helps:)