Answer:
The given equation tells the relationship between the velocity and the length of skid mark,so simply by putting the given values,we can determine the length of the skid mark.
Given,
v
=
25
miles/ hrs=
25
⋅
(
5280
3600
)
f
t
s
i.e
36.67
f
t
s
f
=
0.5
So,from the equation,we get the length of the skid mark=
d
=
36.67
√
32
⋅
0.5
i.e
12.98
f
tExplanation:
Answer:
d. 332 V
Explanation:
Given;
number of turns in the wire, N = 40 turns
area of the coil, A = 0.06 m²
magnitude of the magnetic field, B = 0.4 T
frequency of the wave, f = 55 Hz
The maximum emf induced in the coil is given by;
E = NBAω
Where;
ω is angular velocity = 2πf
E = NBA(2πf)
E = 40 x 0.4 x 0.06 x (2 x π x 55)
E = 332 V
Therefore, the maximum induced emf in the coil is 332 V.
The correct option is "D"
d. 332 V
If the rod is in rotational equilibrium, then the net torques acting on it is zero:
∑ τ = 0
Let's give the system a counterclockwise orientation, so that forces that would cause the rod to rotate counterclockwise act in the positive direction. Compute the magnitudes of each torque:
• at the left end,
τ = + (50 N) (2.0 m) = 100 N•m
• at the right end,
τ = - (200 N) (5.0 m) = - 1000 N•m
• at a point a distance d to the right of the pivot point,
τ = + (300 N) d
Then
∑ τ = 100 N•m - 1000 N•m + (300 N) d = 0
⇒ (300 N) d = 1100 N•m
⇒ d ≈ 3.7 m
Kinetic energy equation is given:
Substituting our known variables, we get:
KE = 51484.375J
Hope this helps!