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Sever21 [200]
3 years ago
6

Newton’s second law states that the acceleration a of an object is proportional to the force F acting on it is inversely proport

ional to its mass m. That is, a = F / mWhat are the dimensions of force?
Physics
1 answer:
netineya [11]3 years ago
5 0

Answer:

[F]=[MLT^{-2}]

Explanation:

Newton’s second law states that the acceleration a of an object is proportional to the force F acting on it is inversely proportional to its mass m. The mathematical expression for the second law of motion is given by :

F = m × a

F is the applied force

m is the mass of the object

a is the acceleration due to gravity

We need to find the dimensions of force. The dimension of force m and a are as follows :

[m]=[M]

[a]=[LT^{-2}]

So, the dimension of force F is, [F]=[MLT^{-2}]. Hence, this is the required solution.

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An object's true weight is 123 N. When it is completely submerged in water, its
SashulF [63]

Object true weight is given as

mg = 123 N

now we know that g = 9.8 m/s^2

m* 9.8 = 123

m = \frac{123}{9.8} = 12.55 kg

now when it is complete submerged in water its apparent weight is given as 82 N

apparent weight = weight - buoyancy force

apparent weight = 82 N

weight = 123 N

now we have

82 = 123 - buoyancy force

buoyancy force = 123 - 82 = 41 N

now we also know that buoyancy force is given as

F_b = p_{liq}Vg

41 = 1000*V*9.8

V = \frac{41}{1000*9.8}

V = 4.18 * 10^{-3} m^3

now as we know that mass of the object is 12.55 kg

its volume is 4.18 * 10^-3 m^3

now we know that density will be given as mass per unit volume

density = \frac{m}{V}

density = \frac{12.55}{4.18*10^{-3}

density = 3002.4 kg/m^3

so here density of object is 3002.4 kg/m^3

7 0
3 years ago
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A double-slit arrangement produces bright interference fringes for sodium light ( λ = 603 nm) that are angularly separated by 0.
ohaa [14]

Answer:

θ for water = 0.3684°

Explanation:

given data

wavelength  λ = 603 nm

angle θ = 0.49°

index of refraction n =  1.33

to find out

angular fringe separation

solution

we know that double slit interference is here

m λ = d sin(θ)    .................1

so for air it will be

m λ(air) = d sin(θ)air        ...........2

and for water it will be

m λ(water) = d sin(θ)water       .............3

now we take here ratio of equation 2 and 3

\frac{\lambda (water)}{\lambda(air)} = \frac{sin(\Theta)water}{sin(\Theta)air}      

and

ratio of wavelength is = \frac{1}{n}

ratio of wavelength  = \frac{1}{1.33}

ratio of wavelength  = 0.75187

so

sin(θ)water = sin(θ)air (0.75187)

sin(θ)water = sin(0.49) (0.75187)

sin(θ)water = 0.006429

so (θ)water  is

(θ)water = 0.3683°

we notice here that by using small angle formula

we have approximate sin(θ) = θ

so θ for water is = \frac{\Theta }{n}

θ for water = \frac{0.49}{1.33}

θ for water = 0.3684°

7 0
3 years ago
A ball is thrown downward with an initial velocity of 3.8 m/s. What is its acceleration?
hammer [34]
I think it’s 0 m/s because usually what I remember is when velocity is moving the acceleration is constant
6 0
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In one of the classic nuclear physics experiments at the beginning of the 20th century, an alpha particle was accelerated toward
lukranit [14]

Answer:

3.8 × 10 ⁻¹⁴ m

Explanation:

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Charge of the alpha particle q₁= 2 × 1.6 × 10⁻¹⁹ C = 3.2 × 10⁻¹⁹ C

Charge of the gold nucleus q₂= 79 × 1.6 × 10⁻¹⁹ = 1.264 × 10⁻¹⁷C

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k electrostatic force constant = 9 × 10⁹ N.m²/c²

Kinetic energy = potential energy =   k q₁q₂ / r where r is the closest distance the alpha particle got to the gold nucleus

r = (  9 × 10⁹ N.m²/c² × 3.2 × 10⁻¹⁹ C × 1.264 × 10⁻¹⁷C) / 9.564 × 10⁻¹³ = 3.8 × 10 ⁻¹⁴ m

6 0
2 years ago
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Answer:

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Explanation:

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