Question

An experiment in a general chemistry laboratory calls for a 2.00 M solution of HCL. How many mL of 11.9 M HCL would be required to make 250 mL of 2.00 M HCL?

Answer 1

Answer: The volume of concentrated solution required is 42 mL

Explanation:

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted solution

We are given:

$M_1=11.9M\\V_1=?mL\\M_2=2.0M\\V_2=250mL$

Putting values in above equation, we get:

$11.9\times V_1=2.0\times 250\\\\V_1=42mL$

Hence, the volume of concentrated solution required is 42 mL