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3 years ago

Explain why the elements of groups 1 and 7 are mostly used in the form of compound

1 answer:

8 0

Group 1 and group 7 of element group consists of alkali metal, which are generally combined with other elements in nature, so they have properties of compound

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Using spectroscopic notation write the complete electron configuration for the fluorine atom. Using noble gas notation write the

prohojiy [21]

Explanation:

Flourine has atomic number of 9 and hence 9 electrons in its neutral state. The full electronic configuration is given as;

1s2 2s2 2p5

Carbon has atomic number of 6 and hence 6 electrons in it's neutral state. The noble gas notation as the following format;

[closest noble gas before the element] remaining electrons

The nearest noble gas to carbon is Helium, the noble gas notation is given as;

[He] 2s4

3 0

3 years ago

Jim and Jan were racing in a 400 meter event. Jim ran the race in 44.32 seconds. Jan ran the race in 42.21 seconds. Calculate th

nordsb [41]

Answer:

2.11

Explanation:

44.32- 42.21=2.11

Hope this helps

4 0

3 years ago

Read 2 more answers

Determine the correct name for the compound, Mg3N2. A) Manganese nitride B) Magnesium nitride Eliminate C) Magnesium (II) nitrid

kotegsom [21]

Magnesium Nitride, :)

4 0

3 years ago

Read 2 more answers

How many moles of zinc, Zn, are in 1.31×1024 Zn atoms?

liubo4ka [24]

Answer:

=7.89013× 10^47 moles of zinc

Explanation:

1 atom contains 6.023×10^23 moles.

1.31×10^24 atoms of zinc contain6.023×10^24×1.31×10^.24

6 0

2 years ago

A florist prepares a solution of nitrogen-phosphorus fertilizer by dissolving 5.66 g of NH₄NO₃ and 4.42 g of (NH₄)₃ PO₄ in enoug

Alexandra [31]

In finding the molarity of a solution, we use the following formula:

$M=moles soluteL solution$

What is Molarity?

The number of moles of the solute is calculated by dividing the mass of the solute by its molar mass.

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The molar mass of NH4NO3 and (NH4)3PO4 are 80.043 g/mol and 149.0867 g/mol, respectively.

$molesNH+4inNH4NO3=5.66 g80.043 g/mol×1molNH+41molNH4NO3=0.0707 mol$

$molesNH+4in(NH4)3PO4=4.42 g149.0867 g/mol×3molNH+41mol(NH4)3PO4=0.0889 mol$

$total molesNH+4=0.0707 mol+0.0889 mol=0.1596 mol$

$molesPO3−4in(NH4)3PO4=4.42 g149.0867 g/mol×1molPO3−41mol(NH4)3PO4=0.0296 mol$

$[NH+4]=0.1596 mol20.0 L=7.98×10−3 M NH+4$

$[PO3−4]=0.0296 mol20.0 L=1.48×10−3 M PO3−4$

Therefore, $[PO3−4]\\$ has a molarity of $1.48×10−3 M PO3−$

To learn more about Molarity click on the link below:

brainly.com/question/19943363

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5 0

2 years ago