Answer:
8.66 g of Al₂O₃ will be produced
Explanation:
4Al (s) + 3O₂ (g) → 2Al₂O₃ (s)
This is the reaction.
Problem statement says, that the O₂ is in excess, so the limiting reactant is the Al. Let's determine the moles we used.
4.6 g / 26.98 g/mol = 0.170 moles
Ratio is 4:2.
4 moles of aluminum can produce 2 moles of Al₂O₃
0.170 moles of Al, may produce (0.170 .2)/ 4 = 0.085 moles
Let's convert the moles of Al₂O₃ to mass.
0.085 mol . 101.96 g/mol = 8.66 g
Answer:
Explanation:
From the question we are told that:
Edge length of the unit cell 
a)
Generally the equation for The relationship between edge length and radius is mathematically given by
Therefore
b)
From the question we are told that:
Density 
Edge length of 
Therefore Volume is given as
Generally the equation for Mass is mathematically given by
Therefore Molarity is given as
Finally The atoms in a unit cell is
I would have to say cholesterol
Answer:
A
Explanation:
With the given choices, A would be correct for this question. But, both liquids and gases have particles that are far apart so that they can fill their containers.
6.7639104*10^0 is the answer.
