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Ber [7]
3 years ago
13

How is the earth’s groundwater and surface water replenished

Chemistry
2 answers:
Oksanka [162]3 years ago
6 0

Answer:

The replenishment of groundwater takes place by precipitation, and on the basis of the geology and local climate, it is non-uniformly dispersed in both the quantity and quality. When the snow melts or rain falls, the evaporation of water takes place, some flows overland and gets gathered in streams, some get transpired by plants, while some infiltrate into the cracks or pores of the rocks and soil. After the requirements of water for the plants and soil gets fulfilled, the excess water gets infiltrate to the water table.  

Similarly, the surface water, that is, the lakes, streams, rivers, and others get replenished via the process of precipitation. This can be in the form of hail, snow, rain, and others. The ice or snow melt also recharges surface water.  

elixir [45]3 years ago
3 0
The water cycle?  hope this helped 
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What is the mass of 11.4 L of NO2
kodGreya [7K]
At STP volume is 22.4 L

Molar mass NO₂ = 46.0 g/mol

1 mole ---------- 22.4 L
? mole ---------- 11.4 L

moles = 11.4 * 1 / 22.4

moles = 11.4 / 22.4

= 0.5089 moles of NO₂

Mass NO₂ :

moles NO₂ * molar mass

0.5089 * 46.0

= 23.4094 g of NO₂

hope this helps!

7 0
3 years ago
Is SiO2 London Dispersion, Dipole-Dipole, or Hydrogen Bonding?
s2008m [1.1K]

Answer:

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Explanation:

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6 0
2 years ago
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Which reaction would cause an increase in entropy? A. SO2Cl2(g) SO2(g) + Cl2(g) B. PCl3(g) + Cl2(g) PCl5(g) C. 2CO(g) + O2(g) 2C
IrinaVladis [17]
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8 0
3 years ago
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aleksandrvk [35]

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4 0
3 years ago
what is the specific heat of a substance if 300 j are required to raise the temperature of a 267-g sample by 12 degrees c
slava [35]

Answer : The specific heat of the substance is 0.0936 J/g °C

Explanation :

The amount of heat Q can be calculated using following formula.

Q = m \times C \times \bigtriangleup T

Where Q is the amount of heat required = 300 J

m is the mass of the substance = 267 g

ΔT is the change in temperature = 12°C

C is the specific heat of the substance.

We want to solve for C, so the equation for Q is modified as follows.

C = \frac{Q}{m \times \bigtriangleup T}

Let us plug in the values in above equation.

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The specific heat of the substance is 0.0936 J/g°C

3 0
3 years ago
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