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Alchen [17]
3 years ago
11

A 13.1-g sample of CaCl2 is dissolved in 104 g of water, with both substances at 24.7°C. Calculate the final temperature of the

solution assuming no heat loss to the surroundings and assuming the solution has a specific heat capacity of 4.18 J °C−1 g−1.
Chemistry
1 answer:
likoan [24]3 years ago
7 0

Answer:

The final temperature of the solution is 44.8 °C

Explanation:

assuming no heat loss to the surroundings, all the heat of solution (due to the dissolving process) is absorbed by the same solution and therefore:

Q dis + Q sol = 0

Using tables , can be found that the heat of solution of CaCl2 at 25°C (≈24.7 °C)  is q dis= -83.3 KJ/mol . And the molecular weight is

M = 1*40 g/mol + 2* 35.45 g/mol = 110.9 g/mol

Q dis = q dis * n  = q dis * m/M =  -83.3 KJ/mol * 13.1 g/110.9 gr/mol = -9.84 KJ

Qdis= -9.84 KJ

Also Qsol = ms * Cs * (T - Ti)

therefore

ms * Cs * (T - Ti) + Qdis = 0

T=  Ti - Qdis * (ms * Cs )^-1   =24.7 °C - (-9.84 KJ/mol)/[(104 g + 13.1 g)* 4.18 J/g°C] *1000 J/KJ

T= 44.8 °C

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mafiozo [28]

Answer:

x = 1, -7.5

Explanation:

2x² + 13x = 15

Divide the left side of the equation by 2

2(x² + 6.5x) = 15

Divide 6.5 by 2 and square the quotient

6.5/2 = 3.25

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Add 10.5625 to the left side

2(x² + 6.5x + 10.5625) = 15

Since you have a 2 outside the parentheses, you will be adding 10.5625•2 to the right side.

10.5625 • 2 = 21.125

2(x² + 6.5x + 10.5625) = 36.125

To factor (x² + 6.5x + 10.5625), add b/2 to x

b/2 = 6.5/2 = 3.25

2(x + 3.25)² = 36.125

Divide by 2

(x + 3.25)² = 18.0625

Square root.

(x + 3.25) = √18.0625

x + 3.25 = ±4.25

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Consider these elements: p, ca, si, s, ga.<br> a. write the electron configuration for each element
dimulka [17.4K]
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2) Use Aufbau rule

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<span>
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Ca              20                            </span><span><span>1s2 2s2 2p6 3s2 3p6 4s2

</span>Si                14</span><span>                            1s2 2s2 2p6 3s2 3p2

S                 16</span><span><span>                            1s2 2s2 2p6 3s2 3p4

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Calculate the amount of grams of water that was used when 5525J of energy was used to boil this amount of water.
djverab [1.8K]

Answer:

2.445 g

Explanation:

Step 1: Given and required data

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  • Latent heat of vaporization of water (∆H°vap): 2260 J/g
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Step 2: Calculate the mass of water

We will use the following expression.

Q = ∆H°vap × m

m = Q / ∆H°vap

m = 5525 J / (2260 J/g)

m = 2.445 g

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