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Dovator [93]
3 years ago
8

Are there more metals or nonmetals on the periodic table?

Chemistry
2 answers:
tensa zangetsu [6.8K]3 years ago
7 0
There are more metals
bogdanovich [222]3 years ago
6 0

Answer:yes

Explanation:

I think so

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Pls help it’s due at 12
likoan [24]

Answer:

it's

D. 2K + 2H2O

Explanation:

it just is

5 0
3 years ago
The enthalpy of solution (∆H) of KOH is -57.6 kJ/mol. If 3.66 g KOH is dissolved in enough water to make a 150.0 mL solution, wh
Wewaii [24]

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

The enthalpy of solution of KOH is -57.6 kJ/mol. We can calculate the heat released by the solution (Qr) of 3.66 g of KOH considering that the molar mass of KOH is 56.11 g/mol.

3.66g \times \frac{1mol}{56.11g} \times \frac{(-57.6kJ)}{mol} = -3.76 kJ

According to the law of conservation of energy, the sum of the heat released by the solution of KOH (Qr) and the heat absorbed by the solution (Qa) is zero.

Qr+Qa = 0\\\\Qa = -Qr = 3.76 kJ

150.0 mL of solution with a density of 1.02 g/mL were prepared. The mass (m) of the solution is:

150.0 mL \times \frac{1.02g}{mL}  = 153 g

Given the specific heat capacity of the solution (c) is 4.184 J/g・°C, we can calculate the change in the temperature (ΔT) of the solution using the following expression.

Qa = c \times m \times \Delta T\\\\\Delta T = \frac{Qa}{c \times m} = \frac{3.76 \times 10^{3}J  }{\frac{4.184J}{g.\° C }  \times 153g} = 5.87 \° C

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

Learn more: brainly.com/question/4400908

7 0
2 years ago
What is the formula for Manganese (III) acetate?
AURORKA [14]

C6H9MnO6.2(H2O)

Here is the formula hope it helps.

3 0
3 years ago
Read 2 more answers
You need to use a dilute hydrochloric acid solution in an experiment. However, the only bottle of hydrochloric acid in your lab’
mr_godi [17]

The pH of the diluted HCl solution is 1.3.

Explanation:

Given:

The concentrated HCl solution of 8.0 M. The 1.5 mL of 8.0 M HCl is diluted with water to 250 mL volume.

To find:

The pH of the diluted HCl solution.

Solution

  • The concentration of the HCl solution before dilution = M_1=8.0 M
  • The volume of the HCl solution taken for dilution = V_1=1.5 ml
  • The concentration of the HCl solution after dilution =M_2=?
  • The volume of the HCl solution after dilution = V_2=250 mL

Using the Dilution equation:

M_1V_1=M_2V_2\\8.0M\times 1.5ml=M_2\times 250 mL\\M_2=\frac{8.0M\times 1.5ml}{250 mL}=0.048 M

The concentration of diluted HCl solution = 0.048 M

HCl(aq)\rightarrow H^+(aq)+Cl^-(aq)

In the 1 M solution of HCl, there are 1 M of hydrogen ion, then the concentration of hydrogen ions in 0.048 M of HCl will be:

[H^+]=1\times 0.048M=0.048 M

The pH of the diluted HCl solution :

pH=-\log [H^+]\\=-\log [0.048M]=1.18 \approx 1.3

The pH of the diluted HCl solution is 1.3.

Learn more about the dilution equation here:

brainly.com/question/24546169?referrer=searchResults

brainly.com/question/1199928?referrer=searchResults

4 0
2 years ago
Iii. When the boat is fully loaded, it floats lower in the water than when it is empty. Explain
denis23 [38]

Answer:

The loaded ship will weigh more. Thus it will sink down farther in the water in order to displace that much more water so that it continues to float.

5 0
2 years ago
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