The number of mole of lithium, Li needed for the reaction is 3.2 moles (Option D)
<h3>Balanced equation </h3>
4Li + N₂(g) → 2Li₂N
From the balanced equation above,
2 moles of Li₂N were obtained from 4 moles of Li
<h3>How to determine the mole of lithium needed </h3>
From the balanced equation above,
2 moles of Li₂N were obtained from 4 moles of Li
Therefore,
1.6 moles of Li₂N will be obtained from = (1.6 × 4) / 2 = 3.2 moles of Li
Thus, 3.2 moles of Li are needed for the reaction
Learn more about stoichiometry:
brainly.com/question/14735801
Answer:
The two products that will be formed are:
Ca(NO3)2
NaI
Explanation:
When NaNO3 reacts with CaI2, double substitution reaction takes place.
This means that I2 and NO3 will each substitute the other.
The chemical reaction used to explain this is as follows:
2NaNO3 + CaI2 .........> 2NaI + Ca(NO3)2
Hope this helps :)
Answer:
Explanation:
To convert from moles to grams we must use the molar mass, which can be found on the Periodic Table.
- Aluminum (Al): 26.981538 g/mol
Use this number as a fraction.
Multiply by the given number of moles.
The moles of aluminum will cancel.
The original number of moles, 0.500, has 3 significant figures, so our answer must have the same.
For the number we calculated, that is the tenth place. The 9 in the hundredth place tells us to round the 4 to a 5.
There are about <u>13.5 grams of aluminum</u> in 0.500 moles.
"4" is the one coefficient of H+ among the following choices given in the question that <span>balances the atoms in the following half-reaction. The correct option among all the options that are given in the question is the fourth option or the last option. I hope that this is the answer that has actually helped you.</span>
