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3 years ago

A bubble at the bottom of the lake to the surface within 10.0 seconds what is the depth of the lake

1 answer:

7 0

I normal bubble starts at the speed of 10mph then speeds up +5 each second. so this would be 600 meters. also, it depends on the density of the water and whats inside the water or liquid in the lake. there are many factors that will change this speed.

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State two (2) examples of osmosis occurring in everyday life

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3 years ago

A pump jack scaffold must be fitted with two ______ gripping mechanisms to prevent slippage.

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3 years ago

Any 3 differences between telescope and microscope

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4 years ago

The phases of the moon occur because the moon revolves around the earth.<br><br> True<br><br> False

Ira Lisetskai [31]

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4 years ago

A swimmer bounces almost straight up from a diving board and falls vertically feet first into a pool.she starts with a speed of

garik1379 [7]

Answer:

a) 1.20227 seconds

b) 0.98674 m

c) 7.3942875 m/s

Explanation:

t = Time taken

u = Initial velocity = 4.4 m/s

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

$v=u+at\\\Rightarrow 0=4.4-9.81\times t\\\Rightarrow \frac{-4.4}{-9.81}=t\\\Rightarrow t=0.44852\ s$

$s=ut+\frac{1}{2}at^2\\\Rightarrow s=4.4\times 0.44852+\frac{1}{2}\times -9.81\times 0.44852^2\\\Rightarrow s=0.98674\ m$

b) Her highest height above the board is 0.98674 m

Total height she would fall is 0.98674+1.8 = 2.78674 m

$s=ut+\frac{1}{2}at^2\\\Rightarrow 2.78674=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{2.78674\times 2}{9.81}}\\\Rightarrow t=0.75375\ s$

a) Her feet are in the air for 0.75375+0.44852 = 1.20227 seconds

$v=u+at\\\Rightarrow v=0+9.81\times 0.75375\\\Rightarrow v=7.3942875\ m/s$

c) Her velocity when her feet hit the water is 7.3942875 m/s

3 0

3 years ago