(c+8)(c-8)
3(2y+5)(2y-5)
There are no like terms so it's still ab^2-b
Multiply first then you would wanna add but you can't until you subtract 5-3 then add I got 12
Since (4y-42) and 2y are opposite angles, they equal to each other which looks like this:
4y-42 = 2y
From there you want to put the y onto one side:
4y-2y-42=0 -----> 2y-42=0
You want to balance the equation out and move the -42 onto the other side so you add it to both sides to get:
2y=42
Then divide both sides by 2 to get:
y= 21
From there you can plug 21 back into the original equation to find each angle.
4(21)-42 = 2(21) ---> 84-42 = 42 ---> 42 = 42
So y = 21 and each angle is 42 degrees
The trigonometric equation <span> (sin Θ − cos Θ)^2 − (sin Θ + cos Θ)^3 can be simplified by:
</span>Using x for Θ:
<span>(sinx - cosx)^2 - (sinx + cosx)^2 </span>
<span>= (sin^2 x - 2sinxcosx + cos^2 x) - (sin^2 x + 2sinxcosx + cos^2 x) </span>
<span>= - 2 sinx cosx - 2 sinx cosx </span>
<span>= - 4 sinx cosx </span>
<span>= - 2sin(2x)
</span>
I hope it has come to your help.