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4vir4ik [10]
4 years ago
7

Unbalanced forces always result in _____________. A) motion B) friction

Physics
2 answers:
alex41 [277]4 years ago
8 0
Answer:
Motion

Explanation:

Newton's law:
object at rest will remain at rest unless acted upon by an unbalanced force

Friction:
Friction is a force that acts in a direction opposite to motion
HACTEHA [7]4 years ago
7 0

Answer:

a) motion

Explanation:

hope it helps!!     :)

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What statement applies to the horizontal rows or periods in the periodic table? A. The properties are all the same. B. The eleme
Sliva [168]
The right answer for the question that is being asked and shown above is that: "C. <span>. The properties change going across each row. " the </span>statement that applies to the horizontal rows or periods in the periodic table is that t<span>he properties change going across each row. </span>
7 0
3 years ago
Please help I'm taking a timed test!
SCORPION-xisa [38]
B. A small rubber ball bouncing near a little girl
8 0
3 years ago
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ad for the distance from the sun tothe earth is 1.5 x 10"m. how long does it take for light from ths sun to reach the eath? give
Alexandra [31]

Answer:

About 8.3 minutes

Explanation:

Use the formula for velocity as the distance covered by the light divided the time it takes: [tex]velocity=\frac{distance}{time}[/tex]

Use the information about the speed of light in vacuum: 300000000 \frac{m}{s} = 3*10^{8} \frac{m}{s}

and the information you are given regarding the distance between Sun and Earth: 1.5 * 10^{11} m

to solve the first velocity equation for the unknown time "t":

velocity=\frac{distance}{time} \\3*10^8\frac{m}{s} =\frac{1.5*10^11 m}{t} \\t=\frac{1.5*10^11 }{3*10^8} s= 500 s

we can convert second into minutes by dividing by 60: 500 s = 500/60 minutes = 8.3333... minutes

5 0
3 years ago
A lead bullet with 30-g of mass traveling at 600 m/s hits a thin iron wall and emerges at a speed of 300 m/s. Suppose 50% of the
TiliK225 [7]

Answer:

liquid state of lead T = 547ºC

Explanation:

The temperature change of the lead bullet can be found by the calorimetry equation  

      Q = m c_{v} ΔT  

Where heat is the energy transferred to lead during the crash, we can find average work  

      W = F x  

With the crash it is very short we can use the average speed of the projectile during the crash  

       v_{m} = (v_{f} + v₀) / 2 = (600 + 300) / 2  

       v_{m} = 450 m / s  

This speed of the projectile inside the wall is very inaccurate, but it is better than using any of the two speeds given (initial and final)  

       W = Δp vm  

       W = (m v_{f} -m v₀) vm  

       W = m ( v_{f} -v₀) vm  

       W = 30 10⁻³ (300-600) 450  

       W = 4050 J  

As we have a shock let's use the momentum  

       I = F t = ΔP  

       F = Δp / t  

Let's replace  

      W = (Dp / t) x  

With the crash it is very short we can use the average speed of the projectile during the crash  

     v_{m} = (v_{f} + v₀) / 2 = (600 + 300) / 2  

     v_{m} = 450 m / s  

This speed of the projectile inside the wall is very inaccurate, but it is better than using any of the two speeds given (initial and final)  

      W = Δp vm  

      W = (m v_{f} -m v₀) vm  

     W = m ( v_{f} -v₀) vm  

     W = 30 10⁻³ (300-600) 450  

     W = 4050 J  

They tell us that 50% of the heat is absorbed by lead  

     Q = 50% W  

     Q = 2025 J  

Let's calculate the temperature , the specific heat of lead is

      cv =  128 J/kg ºC  

     Q = m c_{v} Δt

     ΔT = Q / m c_{v}  

     ΔT = 2025 / 3010⁻³ 128  

     T_{f}= 547C

If we review the periodic table, the melting point of lead is 327.3ºC and the boiling point is 1726ºC, since it has a higher temperature than the lead must be in a liquid state

6 0
4 years ago
How much kinetic energy does a 7.2-kg dog need to make a vertical jump of 1.2 m? (The acceleration due to gravity is 9.8 m/s2.)
V125BC [204]
<span>How much kinetic energy does a 7.2-kg dog need to make a vertical jump of 1.2 m?
</span>Answer:

85 Joule (approx)

Explanation:

Potential energy at highest point

<span><span>P.E = mgh = 7.2 kg × 9.8 m/s2</span>×1.2 m≈85 Joule</span>

This is the kinetic energy required for dog to jump a height of 1.2 m.



hope this helps!

7 0
3 years ago
Read 2 more answers
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