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Free_Kalibri [48]
3 years ago
10

What is the property of a medium that determines the speed of light in the material?

Physics
1 answer:
cupoosta [38]3 years ago
8 0
The speed of light is determined by the medium (material) through which the light is travelling. Light travels faster in a vacuum than it does in any other medium. Light changes speed as it passes from one medium to another. This is called refraction.
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If the Sun and volcanoes were controlling the climate, the climate would
Harman [31]

Answer:

<em>Undergo global warming at a faster rate than what we are seeing currently</em>

Explanation:

Climate can be described as the average weather of a place. The climate of a particular place can be described after looking at the temperature of the place for a year or more.

If factors, such as the Sun and volcanoes controlled climates then there would be an increase in the temperature and more global warming. Volcanoes can be described as heat erupting from mountains which will, of course, lead to global warming.

4 0
3 years ago
How does the currently accepted model of the nucleus provide evidence of the existence of the strong nuclear force?
olganol [36]

Answer:

Protons and neutrons are all attracted to each other as a result - the strong nuclear force. This is an attractive force that only has an effect over a very short range in the nucleus.

4 0
3 years ago
How far will a car travel in 25 seconds at 10m/ min
Kryger [21]
Time = 25s
speed = 10m/min
= 10m / 60
= (1/6)m/s


distance = speed × time
= 25 × (1/6)
=4.167m
7 0
3 years ago
An electric dipole is formed from ±1.00nC charges spaced 3.00 mm apart. The dipole is at the origin, oriented along the x-axis.
Ronch [10]

Answer:

Value of electric field along the axis and equitorial axis  E=31.25\ N/c and E = 15.625\ N/c respectively.

Explanation:

Given :

Distance between charges , d = 3 \ mm =\dfrac{3}{1000}\ m=3\times 10^{-3}\ m.

Magnitude of charges , q=1\ nC = 10^{-9}\ C.

Dipole moment , p=qL=10^{-9}\times 3\times 10^{-3}=3\times 10^{-12} \ C\ m.

Case A) (x,y) = (12.0 cm, 0 cm) :

Electric field of dipole in its axis ,

E=\dfrac{2kp}{r^3}

Putting all values and r=12\times 10^{-2}\ m.

We get , E=31.25\ N/c.

Case B) (x,y) = (0 cm, 12.0 cm) :

Electric field of dipole on equitorial axis ,

E = \dfrac{kp}{r^3}

Putting all values and r=12\times 10^{-2}\ m.

We get , E = 15.625\ N/c.

Hence , this is the required solution.

7 0
3 years ago
A force of 10 n acts on a mass of 5 kg producing an acceleration of 1.5 m/s2 what is the magnitude of the force of friction acti
prisoha [69]
The friction is 2.5N. The Net force is 10 N - 2.5 N .= 7.5 N.
acceleration = 7.5 / 5 = 1.5 m/s^2
8 0
3 years ago
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