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kogti [31]
3 years ago
6

A 15.75-g piece of iron absorbs 1086.75 joules of heat energy, and its temperature changes from 25°C to 175°C. Calculate the spe

cific heat capacity of iron.
Physics
1 answer:
Ber [7]3 years ago
7 0

Answer:

0.46 J/gC

Explanation:

The specific heat capacity of a material is given by:

C_s = \frac{Q}{m \Delta T}

where

Q is the amount of heat absorbed

m is the mass

\Delta T is the variation of temperature

For the piece of iron in the problem:

m = 15.75 g

Q=1086.75 J

\Delta T=175 C-25 C=150^{\circ}

Substituting into the equation,

C_s = \frac{1086.75 J}{(15.75 g)(150^{\circ}C)}=0.46 J/gC

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