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2 years ago

Which system helps regulate fluids in the body?

Physics

2 answers:

Yanka [14]2 years ago

6 0

Urinary system, hopefully i could help

Harman [31]2 years ago

4 0

The answer is A. Urinary system

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A lamp has a power of 120 W and is left on for 24 hours . A television has a power of 350 W and is left on for three hours . com

Paladinen [302]

This is a power problem which requires the rearranging of a formula. The lamps energy used is 5 N, and the TV’s usage is 116.7 N (rounded from 116.6666repeating). Here my work:

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2 years ago

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The distance vs. time graph of a car moving at constant speed should be a straight line. Why do the data points in the graph plo

iragen [17]

Answer:

The measurements are inexact

Explanation:

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2 years ago

What is kinematics?<br>explain!!~

KIM [24]

Answer:

it is an 3d array of structure which involves inopperation methods

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What is the wave length if the distance from the central bright region to the sixth dark fringe is 1.9 cm . Answer in units of n

Yuri [45]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The wavelength is $\lambda = 622 nm$

Explanation:

From the question we are told that

The distance of the slit to the screen is $D = 5 \ m$

The order of the fringe is m = 6

The distance between the slit is $d = 0.9 \ mm = 0.9 *10^{-3} \ m$

The fringe distance is $Y = 1.9 \ cm = 0.019 \ m$

Generally the for a dark fringe the fringe distance is mathematically represented as

$Y = \frac{[2m - 1 ] * \lambda * D }{2d}$

=> $\lambda = \frac{Y * 2 * d }{[2*m - 1] * D}$

substituting values

=> $\lambda = \frac{0.019 * 2 * 0.9*10^{-3} }{[2*6 - 1] * 5}$

=> $\lambda = 6.22 *10^{-7} \ m$

$\lambda = 622 nm$

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2 years ago

Um ônibus percorre a distância de 480 km, entre Santos e Curitiba, com velocidade escalar média de 80 km/h. De Curitiba a Floria

Mariulka [41]

Answer:

10 h

Explanation:

velocidade é a taxa de variação da distância no tempo. é a razão entre a distância e o tempo

de Santos e Curitiba:

distância (d) de 480 km, velocidade (s) de 80 km/h

$s=\frac{d}{t}\\ t=\frac{d}{s} =\frac{480}{80}=6h$

de Curitiba e Florianópolis:

distância (d) de 300 km, velocidade (s) de 75 km/h

$s=\frac{d}{t}\\ t=\frac{d}{s} =\frac{300}{75}=4h$

tempo médio de ônibus entre Santos e Florianópolis = 6h + 4h = 10h

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2 years ago

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