Can anyone help me with inverse function please?

Mathematics

1 answer:

12345 [234]3 years ago

4 0

${h}^{ - 1} oh(x) = x \\ {h}^{ - 1} (4x + m) = x \\ 2k(4x + m) + \frac{5}{8} = x \\ 8kx + 2km + \frac{5}{8} = x$

k and m must satisfy 8k = 1 mean k = ⅛

and 2km+⅝=0 mean m = -5/2

You might be interested in

The sum of all three numbers is 12. The sum of twice the first number, 4 times the second number, and 5 times the third number i

grigory [225]

Answer:

The numbers are 7, 4 and 1

Step-by-step explanation:

Let the numbers =x, y, z.

The sum of all three numbers is 12, x+y+z=12--------i

The sum of twice the first number, 4 times the second number, and 5 times the third number is 35, 2x+4y+5z=35-------ii

The difference between 8 times the first number and the second number is 52, 8x-y=52---------iii

Now, from (i),z =1-x-y--------iv

substitute (iv) in (ii),

2x+4y+5(12-x-y)=35

2x+4y+60-5x-5y=35

collect like terms

-3x-y=-25

that is, 3x-y=25--------v

solving (iii) and (v) simultaneously (add iii and v), we have

11x=77

divide both sides by 11 to obtain x=7

Put x=7 in (v)

3(7)+y=25

21+y=25

implies y=25-21=4

put x=7 and y=4 in (iv)

z=12-7-4=1

Hence, the numbers are 7, 4 and 1.

5 0

3 years ago

Find the area of the triangle

Archy [21]

Step-by-step explanation:

total base length has to be found.

(√(3.6)^2+(3.25)^2+6.2)*3.25*.5=3.97

6 0

2 years ago

Solve −3x2 − 4x − 4 = 0

kkurt [141]

This is a quadratic formula with a general form of a²x + bx + c = 0. For quadratic equations, we can solve for its two roots using the quadratic formula shown in the attached picture.

a = -3
b = -4
c = -4

x = [-(-4) + √(-4)² - 4(-3)(-4)]/2(-3) = <em>2 + √-32/2</em>
x = [-(-4) - √(-4)² - 4(-3)(-4)]/2(-3) =<em> 2 - √-32/2</em>