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Allisa [31]
3 years ago
12

Copper has two isotopes. The one isotope (Copper-63) has an abundance of 69.2% and a mass of 62.930 amu. The second isotope (Cop

per-65) has an abundance of 30.8% and a mass of 64.928 amu. Calculate the average atomic mass of copper. 62.930 amu 63.545 amu 63.929 amu 64.928 amu
Chemistry
1 answer:
Step2247 [10]3 years ago
8 0
Multiply the percentage by the mass for both and add them to get 63.545 amu 
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In Charles's law, gas volume is directly related to the Celsius temperature.
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Yes this is true gas is related to the celcuis temp
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Which type of scientist would most likely study how electricity could be
miv72 [106K]

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A physicist

Explanation:

Physics is that aspect of science that deals with nature and matter in relation to energy. Electricity is a source for energy

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2 years ago
Enter ionic and net equations: feso4(aq)+ na3po4(aq) arrow fe3(po4)2(s)+na2so4(aq)
stepan [7]

Answer:

<em> ionic equation : </em>3Fe(2+)(aq) + 3SO4(2-)(aq)+ 6Na(+)(aq) + 2PO4 (3-) (aq) → Fe3(PO4)2(s)+ 6Na(+) + 3SO4(2-)(aq)

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Explanation:

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<em>Ionic equations: </em>Start with a balanced molecular equation.  Break all soluble strong electrolytes (compounds with (aq) beside them) into their ions . Indicate the correct formula and charge of each ion. Indicate the correct number of each ion . Write (aq) after each ion .Bring down all compounds with (s), (l), or (g) unchanged. The coefficents are given by the number of moles in the original equation

3Fe(2+)(aq) + 3SO4(2-)(aq)+ 6Na(+)(aq) + 2PO4 (3-) (aq) → Fe3(PO4)2(s)+ 6Na(+) + 3SO4(2-)(aq)

<em>Net ionic equations: </em>Write the balanced molecular equation.  Write the balanced complete ionic equation.  Cross out the spectator ions, it means the repeated ions that are present.  Write the "leftovers" as the net ionic equation.

3Fe(2+)(aq)  + 2PO4 (3-)(aq) → Fe3(PO4)2(s)

6 0
3 years ago
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castortr0y [4]

Answer:

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7 0
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calculate the water potential of a solution of 0.15m sucrose. the solution is at standard temperature.
Mrac [35]

Answer:

The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.

Explanation:

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We have :

C = 0.15 M, T = 273.15 K

i = 1

The water potential of a solution of 0.15 m sucrose= P_w

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