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Kryger [21]
3 years ago
5

How much heat must be removed from 456 g of water at 25.0°c to change it into ice at?

Chemistry
1 answer:
N76 [4]3 years ago
5 0
This question can be simply solved by using heat formula,
    Q = mCΔT

Q = heat energy (J)
m = Mass (kg)
C = Specific heat capacity (J / kg K)
ΔT = Temperature change (K)

when water freezes, it produces ice at 0°C (273 K)
hence the temperature change is 25 K (298 K - 273 K)
C for water is 4186 J / kg K or 4.186 J / g K
By applying the equation,
 Q = 456 g x 4.186 J / g K x 25 K
     = 47720.4 J
     = 47.72 kJ

hence 47.72 kJ of heat energy should be removed.
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Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reactionP4(g) + 10 Cl2(g) → 4PCl5(s) ΔH°r
weqwewe [10]

Answer:

Therefore  \bigtriangledown H^\circ_{rxn}= -1835 KJ

Explanation:

Enthalpy is denoted by H.

Enthalpy: Total heat change in a chemical reaction is called enthalpy.

The change of entalpy of a reaction is denoted by \bigtriangledown H^\circ_{rxn}

Hass's Law:The change in enthalpy of any process can be determined by calculating the sum of change in enthalpy of each of the steps involved in the process.

g= gas

S= solid

P₄(g)+10Cl₂(g)→ 4Cl₅(s)       \bigtriangledown H^\circ_{rxn}=?

PCl₅(s)→ PCl₃(g)+Cl₂(g) .......(1)       \bigtriangledown H^\circ_{rxn}= +157KJ

P₄(g)+6Cl₂(g)→  4PCl₃(g).............(2)     \bigtriangledown H^\circ_{rxn}= -1207 KJ

If we flip a reaction the value of enthalpy will be change positive to negative or nagative to positive but the numerical value will be remain same.

We need rearrange the equation (1) because in the required equation Cl₂ is on the left side. So we flip the first equation.

PCl₃(g)+Cl₂(g)→PCl₅(s)......(3)          \bigtriangledown H^\circ_{rxn}= -157KJ

Multiplying 4 with equation (3)

4 PCl₃(g)+4Cl₂(g)→4PCl₅(s)......(4)          \bigtriangledown H^\circ_{rxn}=4×( -157)KJ= -628 KJ

Adding equation (2) and (4) we get

P₄(g)+6Cl₂(g)+4 PCl₃(g)+4Cl₂(g)→4PCl₃(g)+4PCl₅(s)    \bigtriangledown H^\circ_{rxn}=( -1207-628)KJ

⇒P₄(g)+10Cl₂(g)→4PCl₃(g)-4PCl₃(g)+4PCl₅(s)      \bigtriangledown H^\circ_{rxn}= - 1835KJ

⇒P₄(g)+10Cl₂(g)→ 4Cl₅(s)       \bigtriangledown H^\circ_{rxn}= -1835 KJ

Therefore  \bigtriangledown H^\circ_{rxn}= -1835 KJ

5 0
3 years ago
Why does the particle of water at 0 degree celcius have more energy as cimparrd to the particles in ice at the same temperature?
jekas [21]
There is Kinetic energy involved in the state something is in. The molecules in a liquid are moving around quicker than those in a solid. 

That's one reason.

The ice requires energy to melt. Bonds must be broken to get from a solid to a liquid.

5 0
4 years ago
The mass number of an atom is equal to which of the following?
Phantasy [73]
Mass number is equal to the number of protons plus the number of neutrons in a nucleus of an atom
4 0
3 years ago
What is the formula of a compound formed between iodine (I) and calcium (Ca)?
Nadya [2.5K]
Calcium iodide (chemical formula <span>CaI2</span>)
7 0
3 years ago
Read 2 more answers
A voltaic cell is made using a lead electrode and copper electrode. The electrolytes for each half cell are lead nitrate and cop
lisov135 [29]

The cell notation is Pb_{(s)}  Pb^{2+} _{(aq)} ║Cu^{+2}_{aq}  Cu_{(s)} and the cell potential is 0.464

The reaction occurred while losing of hydron is known as oxidation reaction

We can also tell that the reaction occurred while gaining of oxygen atom is known as oxidation reaction.

The reaction occurred while gaining of hydrogen is known as reduction reaction or we can say that the reaction occurred while losing oxygen atom is known as reduction reaction

An electrochemical cell's cell potential is defined as the difference in potential between two half cells. The electrons' capacity to go from one half cell to the other is what causes the potential difference. As a result of the chemical reaction being a redox reaction, electrons can travel across electrodes.

Calculating the Cell potential

E°cell  = E°(reduction) - E°(oxidation)

           = 0.34 - (-0.0124)

           = 0.464

Hence the cell potential is 0.464

Learn more about Cell potential here

brainly.com/question/11638563

#SPJ10

6 0
2 years ago
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