As distance increases, the amount of force needed decreases.
<h2>
Explanation:</h2>
<h3>B. Chloroplast</h3>
<em>In </em><em>photosynthesis</em><em> </em><em><u>chloroplast</u></em><em> </em><em>inside</em><em> the</em><em> </em><em>leaf </em><em>contain</em><em> </em><em>chlorophyll</em><em> </em><em>which</em><em> </em><em>captures</em><em> </em><em>light</em><em> </em><em>energy</em><em> </em><em>for</em><em> </em><em>photosynthesis.</em>
<em><u>hope</u></em><em><u> this</u></em><em><u> helps</u></em><em><u> you</u></em>
<em><u>have</u></em><em><u> a</u></em><em><u> good</u></em><em><u> </u></em><em><u>day.</u></em>
The direction of torque τ this method is mathematically given as
D=X
Option A is correct.
<h3>What is the
direction of
torque?</h3>
Generally, the equation for torque is mathematically given as
τ = r X F
Hence to decipher the torque direction with respect to the center of mass of the body due to force F acting on the body at a location indicated by the vector r
- We utilize our right hand.
- Place our right-hand fingers along the path of r
- Place our right-hand palm on F
- Then slowly we sweep r into F.
- The path or direction of the thumb will provide the direction of the torque.
In conclusion, the direction of this method is
D=X Option A.
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Answer:
13
Explanation:
13.0120481928 it is the distance
Answer:
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No; the sample could not be aluminum;
since the density of aluminum, " 2.7 g/cm³ " , is NOT close enough to the density of the sample, " 3.04 g/cm³ " .
________________________________________________
Explanation:
________________________________________________
Density is expressed as "mass per unit volume" ;
in which:
"mass, "m", is expressed in units of "g" (grams); and:
"Volume, "V", is expressed in units of "cm³ " (such as in this problem); or in units of "mL" ;
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{Note the exact conversion: " 1 cm³ = 1 mL " .}.
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The formula for density: D = m/V ;
Given: The density of aluminum is: 2.7 g/cm³.
Given: A sample has a mass of 52.0 g ; and Volume of 17.1 cm³ ; could it be aluminum?
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Let us divide the mass of the sample by the volume of the sample;
by using the formula:
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D = m / V ;
and see if the value is at, or very close to "2.7 g/cm³ ".
If it is, then it could be aluminum.
____________________________________________________
The density for the sample:
D = (52.0 / 17.1) g/cm³ = 3.0409356725146199 g/cm³ ;
→round to "3 significant figures" ;
= 3.04 g/cm³ .
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No; the sample could not be aluminum; since the density of aluminum,
"2.7 g/cm³ " is NOT close enough to the density of the sample,
"3.04 g/cm³ " .
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