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8090 [49]
4 years ago
13

How is carbohydrate consumed in excess converted to fat?

Chemistry
1 answer:
BaLLatris [955]4 years ago
4 0

Indirectly, by converting glucose to acetyl CoA.

Explanation:

When excess carbohydrate is consumed it gets converted to glycogen or fatty acids.

The glucose stores fatty acids by the process of lipogenesis. In this process the end product of glycoloysis ie pyruvate is converted to acetyl CoA. This triglyceride stores the fat in adipose tissues.

In the time of need glucose is brought to use by glycogenolysis and gluconeogenesis.

So, the excess fat gets converted and stored as long chain fatty acid and gets incorporated in phospholipids, cholestrol  and triacyglycerol.

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Vinvika [58]
The answer is D

FeCl3 + 3 NH4OH → Fe(OH)3 + 3 NH4Cl
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2 years ago
Please answer this skskskskskksmsk
Sveta_85 [38]

Answer:see attached photo for answer

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4 0
4 years ago
When naming a binary compound, what ending do you use to represent anions?
spin [16.1K]
I believe You replace the ending of the elements name with -ide. example: magnesium flourine should should be magnesium flouride. 
6 0
3 years ago
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4 0
3 years ago
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Arizona was the site of a 400,000-acre wildfire in June 2002. How much carbon dioxide (CO2) was produced into the atmosphere by
kodGreya [7K]

Answer:

2.97 × 10¹³ g

Explanation:

First, we have to calculate the biomass the is burned. We can establish the following relations:

  • 2.47 acre = 10,000 m²
  • 10 kg of C occupy an area of 1 m²
  • 50% of the biomass is burned

The biomass burned in the site of 400,000 acre is:

400,000acre\times\frac{10,000m^{2} }{2.47acre} \times \frac{10kgC}{m^{2} } \times 50\% = 8.10 \times 10^{9} kgC

Let's consider the combustion of carbon.

C(s) + O₂(g) ⇒ CO₂(g)

We can establish the following relations:

  • The molar mass of C is 12.01 g/mol
  • 1 mole of C produces 1 mole of CO₂
  • The molar mass of CO₂ is 44.01 g/mol

The mass of  produced is CO₂:

8.10 \times 10^{12}gC \times \frac{1molC}{12.01gC} \times \frac{1molCO_{2}}{1molC} \times \frac{44.01gCO_{2}}{1molCO_{2}} =2.97 \times 10^{13} gCO_{2}

4 0
4 years ago
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