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3 years ago

Why do some people, especially those in the music industry, think analog recordings are better?

Chemistry

2 answers:

Minchanka [31]3 years ago

8 0

Answer:

Analog sound tends to be warmer, has more texture and is thought to capture a truer representation of the actual sound.

Explanation:

Hello,

Due to the fact that analog sound tends to be warmer, has more texture and is thought to capture a truer representation of the actual sound it is preferred by the people belonging to the music industry even when it is more expensive than digital recordings which felt to be somewhat cold, technical and perhaps lacking in analog’s nuance but very cheap in comparison with the analog recordings.

Best regards.

max2010maxim [7]3 years ago

4 0

Answer:

Analog recordings copy the original sound.

Explanation:

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3 electron layers in the electron shell and 1 electron in the last electron layer

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Answer:

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3 years ago

2.50 liter of a gas has a pressure of 165. kPa at 25.0°C. If the pressure increases to 600. kPa and the temperature to 100.0°C,

tiny-mole [99]

Answer:

0.861 L

Explanation:

We are given pressure, volume, and temperature, so let's apply the Combined Gas Law:

(P₁V₁)/T₁ = (P₂V₂)/T₂

Convert the temperatures to degrees Kelvin.

25.0°C -> 298 K, 100.0°C -> 373 K

Plug in the initial conditions on the left, then the final/new on the right, and solve for the unknown:

(165(2.5))/298 = (600(V₂))/373

V₂ = (165(2.5)(373))/(298(600))

V₂ = 0.861 L

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3 years ago

Can someone tell me how to draw a atomic model for Cd

tensa zangetsu [6.8K]

Explanation:

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3 years ago

The dissolution of 0.200 l of sulfur dioxide at 19 °c and 745 mmhg in water yields 500.0 ml of aqueous sulfurous acid. The solut

aivan3 [116]

Answer:

$Molarity=1.22\ M$

Explanation:

Given:

Pressure = 745 mm Hg

Also, P (mm Hg) = P (atm) / 760

Pressure = 745 / 760 = 0.9803 atm

Temperature = 19 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (19 + 273.15) K = 292.15 K

Volume = 0.200 L

Using ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.9803 atm × 0.200 L = n × 0.0821 L.atm/K.mol × 292.15 K

⇒n = 0.008174 moles

From the reaction shown below:-

$H_2SO_3+2NaOH\rightarrow Na_2SO_3+2H_2O$

1 mole of $H_2SO_4$ react with 2 moles of $NaOH$

0.008174 mole of $H_2SO_4$ react with 2*0.008174 moles of $NaOH$

Moles of $NaOH$ = 0.016348 moles

Volume = 13.4 mL = 0.0134 L ( 1 mL = 0.001 L)

So,

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity=\frac{0.016348}{0.0134}\ M$

$Molarity=1.22\ M$

8 0

3 years ago