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3 years ago

Why do some people, especially those in the music industry, think analog recordings are better?

Chemistry

2 answers:

Minchanka [31]3 years ago

8 0

Answer:

Analog sound tends to be warmer, has more texture and is thought to capture a truer representation of the actual sound.

Explanation:

Hello,

Due to the fact that analog sound tends to be warmer, has more texture and is thought to capture a truer representation of the actual sound it is preferred by the people belonging to the music industry even when it is more expensive than digital recordings which felt to be somewhat cold, technical and perhaps lacking in analog’s nuance but very cheap in comparison with the analog recordings.

Best regards.

max2010maxim [7]3 years ago

4 0

Answer:

Analog recordings copy the original sound.

Explanation:

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Identify six elements common to organic compounds.

valentinak56 [21]

Carbon and hydrogen are present in all
nitrogen is common
sulphur in proteins is common
oxygen is common in ethanoic acids
phosphorus is common for phosphate sugars

hope that helps

4 0

3 years ago

Determine the moles of H+ reacting with the metal based on the following experimental data. 10.00 mL of 1.00 M HCl solution is a

musickatia [10]

Answer:

Approximately $1.876 \times 10^{-3}\; \rm mol$ .

Explanation:

Convert both volumes to standard units (that is: liters.)

$10.00 \; \rm mL = 10.00 \times 10^{-3}\; \rm L = 1.000 \times 10^{-2}\; \rm L$ .
$27.08 \; \rm mL = 27.08 \times 10^{-3}\; \rm L = 2.708 \times 10^{-2}\; \rm L$ .

Number of moles of $\rm HCl$ initially present (in the $10.00\; \rm mL$ solution at $1.00\; \rm M$ .)

$n(\mathrm{HCl}, \, \text{initial}) = \displaystyle c \cdot V = 1.00\times 1.000 \times 10^{-2}= 1.000\times 10^{-2}\; \rm mol$ .

Number of moles of $\rm NaOH$ from the titration:

$n(\mathrm{NaOH}) = c \cdot V = 0.30 \times 2.708 \times 10^{-2} = 8.124 \times 10^{-3}\; \rm mol$ .

$\rm NaOH$ neutralizes $\rm HCl$ at a $1:1$ ratio:

$\rm HCl + NaOH \to NaCl + H_2O$ .

Hence, $n(\mathrm{HCl},\, \text{leftover}) = n(\mathrm{NaOH}) = 8.124 \times 10^{-3}\; \rm mol$ .

$\begin{aligned}&n(\mathrm{HCl},\, \text{consumed}) \\ =& n(\mathrm{HCl},\, \text{initial}) - n(\mathrm{HCl},\, \text{leftover}) \\ =& 1.000\times 10^{-2} - 8.124\times 10^{-3} \\ =& 1.876 \times 10^{-3}\; \rm mol\end{aligned}$ .

3 0

2 years ago

Can somebody Answer number 23 please it’s for a exam

qaws [65]

Answer:

I think everything that's there is correct.

Explanation:

Bleach with pH of about 12.5 would be a strong base.

Milk with pH of 6.5 and Blood with pH around 7 would be neutral.

Battery acid with pH below 1 is strong acid and orange juice is weak acid.

8 0

2 years ago

When the reaction shown is correctly balanced, the coefficients are: kclo3 → kcl + o2?

notka56 [123]

From the balanced equation 2KClO3 → 2KCl + 3O2, the coefficients are the following:
coefficient 2 in front of potassium chlorate KClO3
coefficient 2 in front of potassium chloride KCl
coefficient 3 in front of oxygen molecule O2

We got this balanced equation by identifying the number of atoms of each element that we have in the given equation KClO3 → KCl + O2.
Looking at the subscripts of each atom on the reactant side and on the product side, we have
KClO3 → KCl + O2
   K=1 K=1
Cl=1 Cl=1
O=3 O=2

We can see that the oxygens are not balanced. We add a coefficient 2 to the 3 oxygen atoms on the left side and another coefficient 3 to the 2 oxygen
atoms on the right side to balance the oxygens:
2KClO3 → KCl + 3O2
The coefficient 2 in front of potassium chlorate KClO3 multiplied by the subscript 3 of the oxygen atoms on the left side indicates 6 oxygen atoms just as the coefficient 3 multiplied by the subscript 2 on the right side indicates 6 oxygen atoms.

The number of potassium K atoms and chloride Cl atoms have changed as well:
2KClO3 → KCl + 3O2
   K=2 K=1
   Cl=2 Cl=1
    O=6 O=6

We now have two potassium K atoms and two chloride Cl atoms on the reactant side, so we add a coefficient 2 to the potassium chloride KCl on the product side:
2KClO3 → 2KCl + 3O2, which is our final balanced equation.
K=2 K=2
Cl=2 Cl=2
O=6 O=6
The potassium, chlorine, and oxygen atoms are now balanced.

5 0

2 years ago

Read 2 more answers

What is the valence electron configuration for the oxygen atom

Lana71 [14]

Oxygen has six valence (outer-shell) electrons so therefore gains two more electrons to form the O-2 ion Its electron configuration is: 1s2 2s2 2p6 or Ne

If this helped mark Brainliest!

8 0

2 years ago