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Alexxandr [17]
3 years ago
10

NaOH + HCl → NaCl + H2O. What mass of water forms when 2.75 × 10–4 mol NaOH reacts completely? given the equation, 2.75 × 10–4 m

ol NaOH = ___ g H2O
Chemistry
2 answers:
Nataly [62]3 years ago
6 0

Answer:

0.00496

Explanation:

on edg i just did the assignment teehee

Hoochie [10]3 years ago
5 0
The balanced chemical reaction is written as:

<span>NaOH + HCl → NaCl + H2O

We are given the amount of sodium hydroxide to be used up in the reaction. This will be the starting point for the calculation. 

2.75 x 10^-4 mol NaOH ( 1 mol H2O / 1 mol NaOH ) ( 18.02 g H2O / 1 mol H2O ) = 4.96 x 10^-3 g H2O</span>
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prisoha [69]

Answer : The half life of 28-Mg in hours is, 6.94

Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

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k = rate constant

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a = initial amount of the reactant disintegrate = 53500

a - x = amount left after decay process disintegrate = 53500 - 10980 = 42520

Now put all the given values in above equation, we get

k=\frac{2.303}{48.0}\log\frac{53500}{42520}

k=9.98\times 10^{-2}hr^{-1}

Now we have to calculate the half-life.

k=\frac{0.693}{t_{1/2}}

9.98\times 10^{-2}=\frac{0.693}{t_{1/2}}

t_{1/2}=6.94hr

Therefore, the half life of 28-Mg in hours is, 6.94

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