Answer:
About 5 times faster.
Explanation:
Hello,
In this case, since the Arrhenius equation is considered for both the catalyzed reaction (1) and the uncatalized reaction (2), one determines the relationship between them as follows:
![\frac{k_1}{k_2}=\frac{Aexp(-\frac{Ea_1}{RT} )}{Aexp(-\frac{Ea_2}{RT})} \\\frac{k_1}{k_2}=\frac{exp(-\frac{Ea_1}{RT} )}{exp(-\frac{Ea_2}{RT})}](https://tex.z-dn.net/?f=%5Cfrac%7Bk_1%7D%7Bk_2%7D%3D%5Cfrac%7BAexp%28-%5Cfrac%7BEa_1%7D%7BRT%7D%20%29%7D%7BAexp%28-%5Cfrac%7BEa_2%7D%7BRT%7D%29%7D%20%20%5C%5C%5Cfrac%7Bk_1%7D%7Bk_2%7D%3D%5Cfrac%7Bexp%28-%5Cfrac%7BEa_1%7D%7BRT%7D%20%29%7D%7Bexp%28-%5Cfrac%7BEa_2%7D%7BRT%7D%29%7D)
By replacing the corresponding values we obtain:
![\frac{k_1}{k_2}=\frac{exp(-\frac{55000J/mol}{8.314J/molK*673.15K} )}{exp(-\frac{64000J/mol}{8.314J/molK*673.15K} )} =4.8](https://tex.z-dn.net/?f=%5Cfrac%7Bk_1%7D%7Bk_2%7D%3D%5Cfrac%7Bexp%28-%5Cfrac%7B55000J%2Fmol%7D%7B8.314J%2FmolK%2A673.15K%7D%20%29%7D%7Bexp%28-%5Cfrac%7B64000J%2Fmol%7D%7B8.314J%2FmolK%2A673.15K%7D%20%29%7D%20%3D4.8)
Such result means that the catalyzed reaction is about five times faster than the uncatalyzed reaction.
Best regards.
Answer:
Explanation:Are You From Milo?
Atoms can be the source of both nuclear and chemical energy. Nuclear energy involves the atom's nucleus; chemical energy involves the atom's electrons—subatomic particles that surround the nucleus.
B. false is the answer of this question