Answer:
% yield = 82.5%
Explanation:
HgO + 2Cl₂ → HgCl₂ + Cl₂O
Our reactants are:
Our products are:
We do not have information about moles of reactants, but we do know the theoretical yield and the grams of product, in this case Cl₂O, we have produced.
Percent yield = (Yield produced / Theoretical yield) . 100
Theoretical yield is the mass of product which is produced by sufficent reactant. We replace data:
% yield = (0.71 g/0.86g) . 100 = 82.5%
Answer:
We need 375 milliliters of 0.100 M NaHCO3 solution
Explanation:
Step 1: Data given
Initial molarity NaHCO3 = 0.100 M
Volume prepared solution = 750.0 mL
Molarity prepared solution = 0.05 M
Step 2: Calculate initial volume
C1*V1 = C2V2
⇒with C1 = the initial concentration = 0.100 M
⇒with V1 = The initial volume = TO BE DETERMINED
⇒with C2 = the new concentration = 0.0500M
⇒with v2 = the new volume = 750.0 mL = 0.750 L
0.100 M * V1 = 0.0500 M * 0.750 L
V1 = (0.0500M * 0.750L)/0.100 M
V1 = 0.375 L = 375 mL
We need 375 milliliters of 0.100 M NaHCO3 solution
Hi Lara
The answer is : C
Is equal to
I hope that's help!
The answer is <span>Fluorine my dude
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