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Fiesta28 [93]
3 years ago
7

Near the poles, more energy is reflected back into space than is absorbed. near the poles, more energy is reflected back into sp

ace than is absorbed.
a. True
b. False
Physics
1 answer:
VladimirAG [237]3 years ago
7 0
Correct answer: a) True.

In fact, the soil at the poles consists mainly of snow. Snow has an albedo of 90%: albedo is the fraction of light (and so, of energy) that is reflected back to the space. This means that at the poles, about 90% of the light is reflected back to the space, while only 10% is absorbed.
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tester [92]

Answer:

false

Explanation:

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The velocity of an object is equal to the distance divided by time. The equation is velocity = distance/time. If you wanted to c
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Answer: C) divide: distance ÷ velocity

Explanation:

The velocity V equation is distance d divided by time t:

V=\frac{d}{t}

If we isolate t we will have:

t=\frac{d}{V}

Hence, the correct option is C: distance divided by velocity.

7 0
3 years ago
Which tuning forks will give rise to a beat frequency of 20 Hz when sounded together with a 240 Hz tuning fork?
Lubov Fominskaja [6]

Use the concept of beat frequency to find the applicable final freqeuncy for 20Hz beat frequency.

Beat can be defined as 'the interference pattern between two sounds of slightly different frequencies0

The expression for beat frequency is given as

f_{beat} = |f_1-f_2|

Where,

f_2 = Final frequency

f_1 = Initial frequency

The beat frequency for us is 25Hz and the initial frequency is 240Hz, then

20= |f_2-240|

Being an absolute value, two values are possible, both in addition and subtraction:

f_2 = 240 \pm 20

The two possible values are

f_2 = 220Hz

f_2 = 260Hz

3 0
3 years ago
If an 800 kg roller coaster is at the top of its 50 m high track, it will have a potential energy pf 392,000 J and a kinetic ene
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5 0
3 years ago
During an investigation, a scientist heated 123.6 g of copper carbonate till it decomposed to form a black residue. The total ma
zloy xaker [14]

Answer:

See below explanation

Explanation:

The correspondent chemical reaction for copper carbonate decomposed by heat is:

CuCO₃ (s) → CuO (s) + CO₂ (g)

Considering all molar mass (MM) for each element ( we consider rounded numbers) :

MM CuCO₃ = 123 g/mol

MM CuO = 79 g/mol

MM CO₂ = 44 g/mol

Statement mentions that scientis heated 123.6 g of CuCO₃ (almost a MM), until a black residue is obtained, which weights 79.6 g : this solid residue is formed by CuO, and the remaining mass (approximatelly 44 g) belongs to teh second product, this is, CO₂; as it is a gas compund, it is not certainly included on the solid residue.

So, law of conservation mass is true for this case, since: 123.6 g = 79.6 g + 44 g. As explained, on the solid residue, we don not include the 44 g, which  "escaped" from our system, since it is a gas compound (CO₂)

5 0
3 years ago
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