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gregori [183]
3 years ago
15

The same force is applied to two skateboards. One rolls across the room and the other moves a few feet and comes to a stop. Wher

e was there more work done? The skateboard that traveled the shorter distance shows more work because there was more resistance. The skateboard that traveled the longer distance shows more work because it was lighter. The skateboard that traveled further shows more work because the distance was greater. The skateboard that traveled the shorter distance shows more work because the force was greater.
Physics
2 answers:
igor_vitrenko [27]3 years ago
8 0

The longer you spend reading and thinking about this question,
the more defective it appears.

-- In each case, the amount of work done is determined by the strength
of the force AND by  the distance the skateboard rolls <em><u>while you're still </u></em>
<em><u>applying the force</u>.   </em>Without some more or different information, the total
distance the skateboard rolls may or may not tell how much work was done
to it.<em>
</em>
-- We know that the forces are equal, but we don't know anything about
how far each one rolled <em>while the force continued</em>.  All we know is that
one force must have been removed.

-- If one skateboard moves a few feet and comes to a stop, then you
must have stopped pushing it at some time before it stopped, otherwise
it would have kept going. 

-- How far did that one roll while you were still pushing it ?

-- Did you also stop pushing the other skateboard at some point, or
did you stick with that one?

-- Did each skateboard both roll the same distance while you continued pushing it ?

I don't think we know enough about the experimental set-up and methods
to decide which skateboard had more work done to it.

Lyrx [107]3 years ago
5 0

Answer: More Work was done by the Skateboard that traveled farther.

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GenaCL600 [577]
(a) We can find the current flowing between the walls by using Ohm's law:
I= \frac{\Delta V}{R}
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I=1.01 \cdot 10^{-11} A

(b) The total charge flowing between the walls is the product between the current and the time interval:
Q=I \Delta t
The problem says \Delta t=0.86 s, so the total charge is
Q=(1.01\cdot 10^{-11} A)(0.86 s)=8.73 \cdot 10^{-12} C

The current consists of Na+ ions, each of them having a charge of e=1.6 \cdot 10^{-19} C. To find the number of ions flowing, we can simply divide the total charge by the charge of a single ion:
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4 0
3 years ago
Calculate the percentage increase in speed of the cyclist when the power output changes from 200 W to 300 W.
Rom4ik [11]

Answer:

<em>50%</em>

Explanation:

Given

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3 years ago
while working out a man performed 2525j of work in 19seconds . what was his power A:132.9w. B:241.5w C 47.975w. D100.5w
Olenka [21]
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Answer:

The maximum emf induced in the ring

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Explanation:

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A = (πD²/4)

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Nw = 2π × 6.25 = 39.29 rad/s

E = 30.5 × 10⁻⁶ × 0.000240625 × 39.29

E = (2.882 × 10⁻⁷) V

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