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VARVARA [1.3K]
3 years ago
5

Calculate the momentum of a 1800 kg elephant charging a hunter at a speed of 7.50 m/s.

Physics
1 answer:
liq [111]3 years ago
8 0

The amount of movement, linear momentum, momentum or momentum is a physical quantity derived from a vector type that describes the movement of a body in any mechanical theory. In classical mechanics, the amount of movement is defined as the product of body mass and its velocity at a given time.

p= mv

Where,

m = mass

v = Velocity

Our values are given as,

m = 1800kg

v = 7.5m/s

Replacing we have that,

p = (1800)(7.5)

p = 13500kg\cdot m/s

Therefore the momentum is 13500kg\cdot m/s

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Answer:

v = 3.81 m/s

Explanation:

First, we will find out the radius (r)

sinΘ = r / L

or

r = LsinΘ

on substituting the values, we get

r = 1.2 × sin18°

or

r = 0.370 m

Now,

The tension (T) can be calculated as

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T = mg / cos18.8°

on substituting the values, we have

T = (2kg x 9.8m/s²) / cos18°

or

T = 20.60 N

Now, applying the equilibrium condition in horizontal direction. we have

\Sigma F_x = ma_c = Tsin\theta = 0

also, the centripetal acceleration a_c=\frac{v}{r}

on substituting the values, we get

m(v² / r) = Tsin18°

v = (rTsin18° / m)

v = [(1.2m)(20.60 × sin18°) / 2kg]

v = 3.81 m/s

5 0
3 years ago
Isaac newton discovered that the color white is created when light passes through a prism. t or f?
kap26 [50]

Answer:

false

Explanation:

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7 0
3 years ago
United States citizens have many ways to participate in national life. The most common form of participation is?
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Explanation:

3 0
2 years ago
The whale shark is the largest of all fish and can have the mass of three adult
ch4aika [34]

Answer:

m = 20,000 kg

Explanation:

Force, F=2.5\times 10^4\ N

Acceleration of the shark, a=1.25\ m/s^2

It is required to find the mass of the shark. Let m is the mass. Using second law of motion to find it as follows :

F = ma

Putting the value of F and a to find m

m=\dfrac{F}{a}\\\\m=\dfrac{2.5\times 10^4}{1.25}\\\\m=20,000\ kg

So, the shark's mass is 20,000 kg.

3 0
3 years ago
A ball is dropped from rest from a height h above the ground. another ball is thrown vertically upwards from the ground at the i
Darya [45]

The position of the first ball is

y_1=h-\dfrac g2t^2

while the position of the second ball, thrown with initial velocity v, is

y_2=vt-\dfrac g2t^2

The time it takes for the first ball to reach the halfway point satisfies

\dfrac h2=h-\dfrac g2t^2

\implies\dfrac h2=\dfrac g2t^2

\implies t=\sqrt{\dfrac hg}

We want the second ball to reach the same height at the same time, so that

\dfrac h2=v\sqrt{\dfrac hg}-\dfrac g2\left(\sqrt{\dfrac hg}\right)^2

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\implies v=\sqrt{hg}

8 0
3 years ago
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