Answer:
C + 2H2 ⇒ CH4
Explanation:
In order to balance a chemical equation you need to make sure that the number of atoms on both sides are equal
C + H2 = CH4
C = 1
H = 2
Products:
C = 1
H = 4
H2 = 2 × 2 = 4
C + 2H2 ⇒ CH4
Hope this helps.
Answer:
A neutralization reaction between an acid and a metal hydroxide produces salt and water.
Explanation:
In a neutralization reaction, an acid and a base are combined according to the following example (hydrochloric acid and sodium hydroxide):
HCl + NaOH ---> H20 + NaCl
They are generated as products: water and a salt, in this case sodium chloride.
Answer:
pH = 1.32
Explanation:
H₂M + KOH ------------------------ HM⁻ + H₂O + K⁺
This problem involves a weak diprotic acid which we can solve by realizing they amount to buffer solutions. In the first deprotonation if all the acid is not consumed we will have an equilibrium of a wak acid and its weak conjugate base. Lets see:
So first calculate the moles reacted and produced:
n H₂M = 0.864 g/mol x 1 mol/ 116.072 g = 0.074 mol H₂M
54 mL x 1L / 1000 mL x 0. 0.276 moles/L = 0.015 mol KOH
it is clear that the maleic acid will not be completely consumed, hence treat it as an equilibrium problem of a buffer solution.
moles H₂M left = 0.074 - 0.015 = 0.059
moles HM⁻ produced = 0.015
Using the Henderson - Hasselbach equation to solve for pH:
ph = pKₐ + log ( HM⁻/ HA) = 1.92 + log ( 0.015 / 0.059) = 1.325
Notes: In the HH equation we used the moles of the species since the volume is the same and they will cancel out in the quotient.
For polyprotic acids the second or third deprotonation contribution to the pH when there is still unreacted acid ( Maleic in this case) unreacted.
9,353 - 1,095 - 5,217 = mN
3,041 = mN
H:C:N= 1,095/1 : 5,217/12 : 3,041/14
H:C:N = 1,095 : 0,43475 : 0,2172
H:C:N = 5,037 : 1,99985 : 0,99912 ≈ 5 : 2 : 1
H₅C₂N (C₂H₅N)
To find the ratio of the the combination for the ion, write the charge of the cation as the subscript for the anion, and the charge of the anion as the subscript of the cation. This will make the charges effectively cancel and you will be left with a neutral ionic compound. Remember, that an ionic compound is made up of a metal and a nonmetal.
For Cr3+ and O2-, you will get the neutral compound to be Cr₂O₃.
The proportion these ions combine in is 2 to 3. 2 ions of Cr3+ and 3 ions of O2-
Your answer is D) 2:3