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aivan3 [116]
3 years ago
6

The gas in an engine cylinder is compressed until it has a volume of 0.045 liter and an absolute pressure of 28 atmospheres. If

the engine cylinder contains 0.020 mole of gas, what is its temperature?
Chemistry
2 answers:
Hatshy [7]3 years ago
7 0

7.7 \times 10^{2} \; \text{K}.

<h3>Explanation</h3>

Units of each quantity:

  • <em>P</em> = 28 atm;
  • <em>V</em> = 0.045 L;
  • <em>n</em> = 0.020 mol;

Ideal gas constant:

R = 0.0820573 \;\text{L} \cdot \text{atm} \cdot \text{K}^{-1} \cdot \text{mol}^{-1}.

Apply the ideal gas law:

T = \dfrac{P \cdot V}{n \cdot R} = \dfrac{{\bf 28} \; \text{atm} \times {\bf 0.045} \;\text{L} }{{\bf 0.020}\; \text{mol} \times {\bf 0.0820573} \;\text{L} \cdot \text{atm} \cdot \text{K}^{-1} \cdot \text{mol}^{-1}} = {\bf 767.76} \; \text{K}.

All data given in this question come with two significant figures. Round the value of <em>T</em> to two significant figures:

T = 767.76 \;\text{K} = 7.7 \times 10^{2} \; \text{K}.

marta [7]3 years ago
7 0

Answer:

It is 770 k for plato and Edmentum when you round up 767.75 to 2 Significant Figures

Explanation:

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