Question

KCl is an ionic salt with a formula weight of 74.54 g/mole.

Answer 1

Answer:

mass of water = 958 g = 0.958 kg

m = 1.48 mol/kg

Explanation:

Given:

MM(KCl)= 74.54 g/mol

M= 1.417 mol/L

density of solution= 1064 g/L

To calculate the mass of water in 1 L of solution, first we have to multiply the molarity of the solution (M) by the molecular weight of KCl (MM):

1.417 mol/L x 74.54 g/mol = 105.62 g/L

As the density of the solution is 1064 g/L, we know that 1 L is equal to 1064 g. So, we have 105.62 g of KCl in 1064 g of solution. The mass of water will be the difference between the mass of solution and the mass of solute:

mass of water (g) = 1064 g - 105.6 g = 958.4 g

mass of water (kg)= 958.4 g x 1 kg/1000 g = 0.958 kg

To determine the molality (m):

m = moles of KCl/kg water

m = 1.417 moles/0.958 kg = 1.479 mol/kg