Question

A nugget of gold with a mass of 521 g is added to 50.0 mL of water. The water level rises to a volume of 77.0 mL. What is the density of the gold?

Answer 1

Displaced volume :

 Vf - Vi

77.0 mL - 50.0 mL => 27 mL

Therefore:

d = m / V

d = 521 / 27

d = 19.29 g/mL