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3 years ago

5

A nugget of gold with a mass of 521 g is added to 50.0 mL of water. The water level rises to a volume of 77.0 mL. What is the de

nsity of the gold?

1 answer:

docker41 [41]3 years ago

6 0

Displaced volume :

<span> Vf - Vi
</span>
77.0 mL - 50.0 mL => 27 mL

Therefore:

d = m / V

d = 521 / 27

d = 19.29 g/mL

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