A nugget of gold with a mass of 521 g is added to 50.0 mL of water. The water level rises to a volume of 77.0 mL. What is the de
nsity of the gold?
1 answer:
Displaced volume :
<span> Vf - Vi
</span>
77.0 mL - 50.0 mL => 27 mL
Therefore:
d = m / V
d = 521 / 27
d = 19.29 g/mL
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