How many neutrons are there in one atom of 107 Ag(silver-107)

Chemistry

2 answers:

SCORPION-xisa [38]2 years ago

6 0

C. because silvers atomic number is 47 so you subtract 47 from 107 to get the number of neutrons

Irina18 [472]2 years ago

3 0

Answer:

$60$

Answer C is correct

Explanation:

Silver has 47 electrons and 47 protons.

So,

$mass \: \: number = protons + neutrons \\ \: \: \: \: \: \: \: \: \: \: \: \: \: 107 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \: \: \: \: \: \: \: \: 47 \: \: \: \: \: \: \: \: \: + \: \: \: \: \: \: \: \: \: \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \: \: \: \: \: \: \: 107 - 47 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \: \: \: \: 60$

You might be interested in

What is the average mass of a single chlorine atom in grams

Archy [21]

<span>If you look at the chlorine box, with the symbol Cl, you see the atomic mass is equal to 35.453 atomic mass units. This is the weighted average mass of chlorine, including its isotopes, as found in nature. This also means that one mole of chlorine atoms has a mass of 35.453 grams.</span>

5 0

2 years ago

Unless otherwise instructed, you may refer to the periodic table in the Chemistry: Problems and Solutions book for this question

Tom [10]

Answer: oxygen

There is the s,p,d and f blocks, from groups 1-2 that is the s block, 13-18 that’s the p block, 3-12 is the d block and the f would be lanthanide(#57-71) and actinide (#89-103).

8 0

2 years ago

The solubility of copper chloride at 20 °C is 73 g/100 g of water. Kiera adds 100 g of copper chloride to 100 g of water and sti

OLEGan [10]

Answer:

$m_{undissolved}=27g$

Explanation:

Hello there!

In this case, according to the given information of the solubility of copper chloride, as the maximum amount of this salt one can dissolve without having a precipitate, we infer that since just 73 grams are actually dissolved, the following amount will remain solid as a precipitate:

$m_{undissolved}=100g-73g\\\\m_{undissolved}=27g$