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MAXImum [283]
3 years ago
7

Please help with 14-16 Thank you!

Chemistry
1 answer:
Natalka [10]3 years ago
4 0
I don't know about 14, but 15 is (4), because a liquid draws in heat to turn into a gas. 16 is (2), because to turn into a cold solid, something has to release heat.
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In the following compound (HCl) How many electrons are gained and lost by each atom?
Verizon [17]

Explanation:

In HCL, one positive atom is given to chlorine from hydrogen so that it can complete it's octate. chlorine take one electron from hydrogen.

In NaCl, Sodium takes one electron from chlorine to complete its orbit with eight electrons. Chlorine gives one electron to sodium.

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3 years ago
Which type of radiation is the main hazard during radiological procedures
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The main <span>hazard </span>is the Radiation and the Gamma rays that are dispersed 
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Marie Curie named polonium in honor of Poland. 1. True or 2. False
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7 0
3 years ago
A 32.2 g iron rod, initially at 21.9 C, is submerged into an unknown mass of water at 63.5 C. in an insulated container. The fin
lorasvet [3.4K]

Answer : The mass of the water in two significant figures is, 3.0\times 10^1g

Explanation :

In this case the heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron metal = 0.45J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of iron metal = 32.3 g

m_2 = mass of water = ?

T_f = final temperature of mixture = 59.2^oC

T_1 = initial temperature of iron metal = 21.9^oC

T_2 = initial temperature of water = 63.5^oC

Now put all the given values in the above formula, we get

32.3g\times 0.45J/g^oC\times (59.2-21.9)^oC=-m_2\times 4.18J/g^oC\times (59.2-63.5)^oC

m_2=30.16g\approx 3.0\times 10^1g

Therefore, the mass of the water in two significant figures is, 3.0\times 10^1g

3 0
3 years ago
A sample of hydrogen peroxide (H202) has 2.0 grams of hydrogen (H) and 32 grams of oxygen (O). What is the percent composition o
Leto [7]

Answer:

O = 94.117%

H = 5.882%

Explanation:

Hydrogen peroxide (H202) Molar Mass = 34g

OH 1-  17g/mol

H 1+ = 1g/mol

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2 Grams H

32 grams O

Percentage composition of  Hydrogen peroxide

O = 32/34 = 94.117%

H =    2/34 =   5.882%

3 0
4 years ago
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