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3 years ago

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Please help me, quick No links !

1 answer:

Simora [160]3 years ago

6 0

"One possibility is that the battle between the virus and your immune system can take as long as two weeks.

It could be the immune system holds the virus at bay,” said Tompkins.

Or, your immune system has to work so hard that after two weeks it’s inflamed and that’s what makes you feel bad.

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What is term redox reaction

mash [69]

An oxidation-reduction (redox<span>) </span>reaction<span> is a type of chemical </span>reaction<span> that involves a transfer of electrons between two species. An oxidation-reduction </span>reaction<span> is any chemical </span>reaction<span> in which the oxidation number of a molecule, atom, or ion changes by gaining or losing an electron.</span>

4 0

3 years ago

Read 2 more answers

La formula estructural del eter butil pentilico

Mama L [17]

Answer:

do you mean?

Explanation:

the structural formula of butyl pentyl ether

3 0

3 years ago

The diagram shows different forms of thermal energy transfer.

Kaylis [27]

Answer:

Conduction

Explanation:

The handle is touching the pot.

And I got it wrong

4 0

3 years ago

Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S2(g)+C(s)↽−−⇀CS2(g)????c=9.40 at 900 K Ho

Maru [420]

Answer : The mass of $CS_2$ is, 555.028 grams

Explanation :

First er have to calculate the concentration of $S_2$ .

$\text{Concentration of }S_2=\frac{\text{Moles of }S_2}{\text{Volume of solution}}=\frac{8.08mole}{5.35L}=1.51mole/L$

Now we have to calculate the concentration of $CS_2$ .

The given balanced chemical reaction is,

$S_2(g)+C(s)\rightleftharpoons CS_2(g)$

Initial conc. 1.51 0 0

At eqm. conc. (1.51-x) (x) (x)

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[CS_2]}{[S_2]}$

Now put all the given values in this expression, we get :

$9.40=\frac{x}{(1.51-x)}$

By solving the term 'x', we get :

x = 1.365 M

Concentration of $CS_2$ = x M = 1.365 M

Now we have to calculate the moles of $CS_2$ .

$\text{Moles of }CS_2=\text{Concentration of }CS_2}\times \text{Volume of solution}=1.365mole/L\times 5.35L=7.303mole$

Now we have to calculate the mass of $CS_2$ .

Molar mass of $CS_2$ = 76 g/mole

$\text{Mass of }CS_2=\text{Moles of }CS_2}\times \text{molar mass of }CS_2}=7.303mole\times 76g/mole=555.028g$

Therefore, the mass of $CS_2$ is, 555.028 grams

3 0

4 years ago

1. A sample of radon has a half-life of 15 hours. What fraction of the sample is left

Hitman42 [59]

I think I learned this

4 0

4 years ago