Answer:
v = 22.54 mph.
Explanation:
Given that,
Distance moved, d = 200 m
Time, t = 19.8 s
We need to find the runner's average speed.
We know that,
1 mile = 1609.34 m
200 m = 0.124 miles
19.8 seconds = 0.0055 h
So,
Speed = distance/time
So, the runner's average speed is 22.54 mph.
Answer:
Initial velocity, u = 23.33 m/s
Explanation:
Given the following data;
Acceleration = 2.5 m/s²
Distance = 4 km to meters = 4000 meters
Time = 0.8 mins to seconds = 0.8 * 60 = 48 seconds.
To find the initial velocity, we would use the second equation of motion;
Where;
S represents the displacement or height measured in meters.
u represents the initial velocity measured in meters per seconds.
t represents the time measured in seconds.
a represents acceleration measured in meters per seconds square.
Substituting into the equation, we have;
4000 = u*48 + ½*2.5*48²
4000 = 48u + 1.25*2304
4000 = 48u + 2880
48u = 4000 - 2880
48u = 1120
Initial velocity, u = 1120/48
Initial velocity, u = 23.33 m/s