To solve this problem we will apply the concepts of speed given the simple harmonic movement, for which it defines this speed as

Here
Angular velocity
A = Amplitude
Recall that the angular velocity is equivalent in terms of the frequency at

If we replace the value we will have then

<em>For mass A </em>

<em>For mass B </em>

Therefore they are equal.
Answer:
zero displacement
its returnin to the starting point.
5 north 5 south
The range of frequencies of visible light in a vacuum is mathematically given as
Fmin=4.19*10^14Hz to Fmax=1*10^15Hz
<h3>What is the range of frequencies of visible light in a vacuum?</h3>
Question Parameters:
The wavelengths of visible light vary from about 300 nm to 700 nm.
Generally, the equation for the frequency is mathematically given as
F=C/\lambda
Therefore
For Fmax

Fmax=1*10^15Hz
Where

Fmin=4.19*10^14Hz
For more information on Wave
brainly.com/question/3004869
Answer;
-Gases
Explanation;
-Pressure can affect the density of gases.
-Density of gases changes with pressure and temperature because gases are compressible fluid and because they are compressible, when pressure increases molecules come closer to each other which means increase in density and when pressure drops molecules of gases become free to expand and get away from each other which density decrease.