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mario62 [17]
3 years ago
10

A self-driving car traveling along a straight section of road starts from rest, accelerating at 2.00 m/s2 until it reaches a spe

ed of 32.0 m/s. Then the vehicle travels for 53.0 s at constant speed until the brakes are applied, stopping the vehicle in a uniform manner in an additional 5.00 s. (a) How long is the self-driving car in motion (in s)? s (b) What is the average velocity of the self-driving car for the motion described? (Enter the magnitude in m/s.) m/s
Physics
2 answers:
valentinak56 [21]3 years ago
6 0

Answer:

t = 75.4 s

v = 26.9 m/s

Explanation:

Part1 :

v1 = 0 m/s

v2 = 32 m/s

a = 2 m/s2

The time needed to reach the final speed is:

v2 = v1 + a*t

32 = 0 + 2*t

t = 16 s

Part 2:

constant speed of 32 m/s for 53 s

Part 3:

v2 = 32 m/s

v3 = 0 m/s

t = 5 s

The acceleration is negative because the car is stopping:

v3 = v2 + a*t

0 = 32 + a*5

a = - 6.4 m/s

a) The total time the car is in motion is:

total time = 16 + 53 + 6.4 = 75.4 s

b) For the average speed you can calculate the total distance and divide it by the total time for an easier way

Part 1

d = (32+0)/2 * 16 = 256 m

Part 2

d = 32 * 53 = 1696 m

Part 3

d = (32+0)/2 * 5 = 80 m

Average speed:

v = (256 + 1696 + 80)/75.4 = 26.9 m/s

slamgirl [31]3 years ago
4 0
V=26.9 m/s
T=75.4s good luck
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A 150-W lamp is placed into a 120-V ac outlet. What is the peak current?
devlian [24]

Answer:

Explanation:

Formula

W = I * E

Givens

W = 150

E = 120

I = ?

Solution

150 = I * 120   Divide by 120

150/120 = I

5/4  = I

I = 1.25

Note: This is an edited note. You have to assume that 120 is the RMS voltage in order to go any further. That means that the peak voltage is √2 times the size of 120. The current has the same note applied to it. If the voltage is its rms value, then the current must (assuming the properties of the bulb do not change)

On the other hand, if the voltage is the peak value at 120 then 1.25 will be correct.

However I would go with the other answerer's post and multiply both values by  √2

3 0
4 years ago
Read 2 more answers
A hose directs a horizontal jet of water, moving with a velocity of 20m/s, on to a vertical wall. The
just olya [345]
Force is defined as the rate of change of momentum.
The initial amount of momentum is mv because water stops when it hit the wall total change of momentum must be \Delta p=mv.
Now let's calculate the force.
F= \frac{dp}{dt}=\frac{d(mv)}{dt}=\frac{dm}{dt}v
We need to find \frac{dm}{dt}. This is the amount of water hiting the wall per second.
\frac{dm}{dt}=\rho Av
Our final formula would be:
F=\rho Avv=\rho Av^2
And now we can calculate the answer:
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6 0
3 years ago
The Jurassic Park ride at Universal Studios theme park drops 25.6 m straight down essentially from rest. Find the time for the d
ankoles [38]

Answer:

V=22.4m/s;T=2.29s

Explanation:

We will use two formulas in order to solve this problem. To determine the velocity at the bottom we can use potential and kinetic energy to solve for the velocity and use the uniformly accelerated displacement formula:

mgh=\frac{1}{2}mv^{2}\\\\X= V_{0}t-\frac{gt^{2}}{2}

Solving for velocity using equation 1:

mgh=\frac{1}{2}mv^{2} \\\\gh=\frac{v^{2}}{2}\\\\\sqrt{2gh}=v\\\\v=\sqrt{2*9.8\frac{m}{s^2}*25.6m}=22.4\frac{m}{s}

Solving for time in equation 2:

-25.6m = 0\frac{m}{s}t-\frac{9.8\frac{m}{s^{2}}t^{2}}{2}\\\\-51.2m=-9.8\frac{m}{s^{2}}t^{2}\\\\t=\sqrt{\frac{51.2m}{9.8\frac{m}{s^{2}}}}=2.29s

7 0
3 years ago
Please left home at 8 AM to spend the day at in amusement park. He arrived at the park, which was 150 KM from his house, at 10 A
antiseptic1488 [7]

Answer:

v=\frac{150km}{2h}=75\frac{km}{h}

Explanation:

We can use the equation for the speed

v=\frac{x}{t}

where x is the distance and t the time. In this case we know that the time spent was 2 hours and the distance was 150km. By replacing we have

v=\frac{150km}{2h}=75\frac{km}{h}

I hope this useful for you

regards

3 0
3 years ago
Everything is perished.........(is it,isn't it, aren't they, are they​
andrey2020 [161]

Answer:

everything is perished isn't it?

hope it helps.

8 0
3 years ago
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