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Leni [432]
4 years ago
6

4(4x+1) = 3x-4(6-x) + 4

Mathematics
2 answers:
brilliants [131]4 years ago
8 0

the answer is -2.2.

hope it helped

alex41 [277]4 years ago
4 0
4(4x+1)=3x-4(6-x)+4
4*4x=3x-24+4x+4
16x=7x-20
9x=20
X=20/9
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Can someone help me with this?
deff fn [24]

Answer:

the answer is 200

Step-by-step explanation:

4 0
4 years ago
Given a force of 10N and an acceleration of 5m/s? What is the mass?
likoan [24]

Answer:

<h3>2kg = mass</h3>

Step-by-step explanation:

<h3>What is the mass?</h3>

Mass is a body of matter without definite shape.

Use the Newton's second law of motion formula.

Note: \longrightarrow \sf{F=M*A}

<u>Given:</u>

  • Force = 10N
  • Acceleration = 5m/s

First thing you do is divide.

10/5=2

= 2kg (mass)

Therefore, the final answer is 2kg (mass).

I hope this helps, let me know if you have any questions.

To learn more about the mass:

brainly.com/question/7580108

5 0
2 years ago
Complete the following <br> a) 3/5 = ?/20<br><br> b) ?/6 = 25=30
vlada-n [284]

Answer:

a) 3/5=12/20

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8 0
3 years ago
Still don’t get it idk lol
KonstantinChe [14]

Answer:

XQ = 12

Step-by-step explanation:

In this question it asks for XQ instead of x, but you need to find x first.

1. Find x.

XQ is half of MQ so this statement is true: 3x - 3 = 2(2x - 6)

Solve for x.

3x - 3 = 2(2x - 6)

Distribute 2.

3x - 3 = 4x - 12

Isolate x.

3x = 4x - 9

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Divide -1 out.

x = 9

Now solve for XQ, which the equation is given.

XQ = 2(9) - 6

XQ = 18 - 6

XQ = 12

6 0
3 years ago
Read 2 more answers
A 50-gallon rain barrel is filled to capacity. It drains at a rate of 10 gallons per minute. Write an equation to show how much
makvit [3.9K]

Answer:

The quantity of water drain after x min is 50 (0.9)^{x}  

Step-by-step explanation:

Given as :

Total capacity of rain barrel = 50 gallon

The rate of drain = 10 gallon per minutes

Let The quantity of water drain after x min = y

Now, according to question

The quantity of water drain after x min = Initial quantity of water ×  (1-\dfrac{\textrm rate}{100})^{\textrm time}

I.e The quantity of water drain after x min = 50 gallon ×  (1-\dfrac{\textrm 10}{100})^{\textrm x}

or,  The quantity of water drain after x min = 50 gallon × (0.9)^{x}

Hence the quantity of water drain after x min is 50 (0.9)^{x}  Answer

4 0
3 years ago
Read 2 more answers
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