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2 years ago

Boo help me please!!!!!!!

Physics

2 answers:

love history [14]2 years ago

7 0

It’s definitely not radiation!

Umnica [9.8K]2 years ago

4 0

Answer:

Explanation:

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Is this a boy or a girl

ivanzaharov [21]

I believe that it is a boy but if they would like to be classified as a girl or a boy their decision needs to be respected

3 0

3 years ago

An electron in orbit around a (one proton) nucleus has a speed of about 106 m/s. Deduce the equivalent current due to the motion

dedylja [7]

Answer:

(a) $-4.8\times 10^{-4}A$ (B) $4.22\times 106{-24}A/m^2$

Explanation:

We have given the the speed of the electron =10^6 m/sec

The time period of the electron is given by $T=\frac{2\pi r}{v}$ where r is the Bohr radius, which is equal to $5.29\times 10^{-11}m$

So time period $T=\frac{2\times \pi \times 5.29\times 10^{-11}}{10^6}=3.324\times 10^{-16}m/sec$

(A) We know that current $i=\frac{q}{T}=\frac{-e}{T}=\frac{-1.6\times 10^{-19}}{3.324\times 10^{-16}}=-4.8\times 10^{-4}A$

(B) Magnetic moment is given by $\mu =IA$ , where I is current and A is area

So $\mu =IA=-4.8\times 10^{-4}\times 3.14\times (5.29\times 10^{-11})^2=4.22\times 10^{-24}A/m^2$

3 0

3 years ago

Which of the following is an obstacle to creating computer-based models for tracking a hurricane?

AnnZ [28]

Forecasters must consider a large number of variables that affect the path of the storm.
This makes it difficult to create computer-based models because all of these variables are hard to incorporate.

5 0

2 years ago

Read 2 more answers

A racecar going around a circular track of radius r begins at rest and then accelerates with a constant linear acceleration a. F

Alex

Can you add the picture

5 0

3 years ago

One side of a triangle is increasing at a rate of 5 cm/sec and a second side is increasing at a rate of 7 cm/sec. If the area of

Vanyuwa [196]

Answer:

The rate of angle is 26.25 rad/sec.

Explanation:

Given that,

First side of triangle a= 20 cm

Second side of triangle b= 50 cm

One side of a triangle is increasing at a rate = 5 cm/sec

Second side is increasing at a rate = 7 cm/s

Angle $\theta=\dfrac{\pi}{3}=60^{\circ}$

If the area of the triangle remains constant,

We need to calculate rate of angle

Using formula of area of triangle

$A=\dfrac{1}{2}ab\sin\theta$

On differentiating

$\dfrac{dA}{dt}=\dfrac{1}{2}ab\cos\theta\dfrac{d\theta}{dt}+\dfrac{1}{2}a\sin\theta\dfrac{db}{dt}+\dfrac{1}{2}b\sin\theta\dfrac{da}{dt}$

Put the value into the formula

$0=\dfrac{1}{2}\times20\times50\cos60\dfrac{d\theta}{dt}+\dfrac{1}{2}\times20\sin60\times7+\dfrac{1}{2}\times50\sin60\times5$

$\dfrac{d\theta}{dt}=\dfrac{35\sqrt{3}\times\dfrac{25}{2}\sqrt{3}\times5}{250}$

$\dfrac{d\theta}{dt}=26.25\ rad/sec$

Hence, The rate of angle is 26.25 rad/sec.

8 0

3 years ago

Boo help me please!!!!!!!​

Boo help me please!!!!!!!