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erastovalidia [21]
3 years ago
8

How can the rate of a reaction be increased?

Chemistry
2 answers:
Nana76 [90]3 years ago
4 0
I think it may be A.
But I'm not sure






Basile [38]3 years ago
4 0
The correct answer is A.

Hope this helps
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Which is the best example of translate translational motion
RoseWind [281]

The correct answer would be A) A soccer ball passed between two players because the ball is in motion.

6 0
3 years ago
Fill in the blanks and balance with the correct coefficient​
MrRissso [65]

\huge\mathrm{  \underline{Answer}}࿐

The Balanced equation will be :

\mathrm{ \boxed2Fe +  \boxed3Cl_2  \rightarrow  \boxed2FeCl_3}

The Coefficients are :

  • Fe - 2

  • Cl_2 - 3

  • FeCl_3 - 2

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4 0
3 years ago
Item 4
Mariulka [41]

Answer:

c

Explanation:

8 0
3 years ago
What is the volume of 0.80 grams of o2 gas at stp? (5 points) group of answer choices 0.59 liters 0.56 liters 0.50 liters 0.47 l
Vladimir [108]

Answer:

0.56L

Explanation:

This question requires the Ideal Gas Law:  PV=nRT where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, R is the Ideal Gas constant, and T is the Temperature of the gas.

Since all of the answer choices are given in units of Liters, it will be convenient to use a value for R that contains "Liters" in its units:R=0.0821\frac{L\cdot atm}{mol\cdot K}

Since the conditions are stated to be STP, we must remember that STP is Standard Temperature Pressure, which means T=273.15K and P=1atm

Lastly, we must calculate the number of moles of O_2(g) there are.  Given 0.80g of O_2(g), we will need to convert with the molar mass of O_2(g).  Noting that there are 2 oxygen atoms, we find the atomic mass of O from the periodic table (16g/mol) and multiply by 2:  32g\text{ }O_2=1mol\text{ }O_2

Thus, \frac{0.80g \text{ }O_2}{1} \frac{1mol\text{ }O_2}{32g\text{ }O_2}=0.25mol\text{ }O_2=n

Isolating V in the Ideal Gas Law:

PV=nRT

V=\frac{nRT}{P}

...substituting the known values, and simplifying...

V=\frac{(0.025 mol \text{ }O_2)(0.0821\frac{L\cdot atm}{mol \cdot K} )(273.15K)}{(1atm)}

V=0.56L \text{ } O_2

So, 0.80g of O_2(g) would occupy 0.56L at STP.

5 0
2 years ago
Read 2 more answers
The diameter of a hydrogen atom is 106 pm. Find the length in kilometers of a row of 4.34 x 1023 hydrogen atoms?
valina [46]

The length in kilometers of a row of 4.34 x 1023 hydrogen atoms is 4.34 x 10¹⁴ km.

<h3>Length of the entire hydrogen atoms</h3>

The length of the entire hydrogen atom is calculated as follows;

Length of the row = number x diameter of one

Length of the row = 4.34 x 10²³ x 10⁶ x 10⁻¹²

Length of the row = 4.34 x 10¹⁷ m

Length of the row = 4.34 x 10¹⁴ km

Thus, the length in kilometers of a row of 4.34 x 1023 hydrogen atoms is 4.34 x 10¹⁴ km.

Learn more about diameter of hydrogen atom here: brainly.com/question/13796082

#SPJ1

3 0
2 years ago
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