I am not sure but this is what I think
This question uses the formula connecting mass, density and volume
Which is Density= Mass/Volume
Convert the mass in g
92.5 kg = 92,500g
7.87g/ml = 92,500/ Volume
Volume= 92,500/7.87
= 11,753.5 ml
Now since we have to give the answer in liters we can just divide by 1000 and get
11.75 litres
The equation for the reaction is:
C₄H₈O₂ + C₂H₅OH = C₆H₁₂O₂ + H₂O
Now you see that the number of the moles of butanoic acid
and etyl butyrate is equal in
the reaction. That means;
number of moles of C₄H₈O₂ = number of moles of C₆H₁₂O₂
mass of C₄H₈O₂/ Molar mass of C₄H₈O₂ = mass of C₆H₁₂O₂/ molar mass of C₆H₁₂O₂
mass of C₆H₁₂O₂ = molar mass of C₆H₁₂O₂ x mass of C₄H₈O₂/ Molar mass of C₄H₈O₂
Now, assuming <span>100% yield, the mass
of ethyl butyrate produced is: </span>
<span>= 7.45/88.11 x 116.16</span>
<span>=9.82g</span>
<span>Thus, the theoretical yield of ethyl butyrate is 9.82g.</span>
The boiling point depends on the strength of the intermolecular forces holding the molecules together. Greater the force, higher is the boiling point.
The intermolecular force increases in the order shown below:
ion-ion > H-bonding > dipole-dipole > London dispersion
CH3CN is a polar molecule with strong dipole-dipole forces
CH3CH2CH3 is non-polar held by london dispersion
Ar exist as a gas. It will have a lowest boiling point
Thus the order of decreasing b.pt is:
CH3CN > CH3CH2CH3 > Ar
Answer:
0.0890 M
Explanation:
Since the concentration of KCl is irrelevant in this case, the concentration of Na2S2O3 can be determined using a simple dilution equation:
C1V1 = C2V2, where C1 = 0.149 M, V1 = 150 mL, V2 = 250 mL
C2 = 0.149 x 150/250
= 0.089 M
To determine the concentration of S2O32- (aq), consider the equation:

The concentration of Na2S2O3 and S2O32- (aq) is 1:1
Hence, the concentration in molarity of S2O32- (aq) is 0.089 M.
To 3 significant figures = 0.0890 M
Answer:
b). of copper (II) sulfate
I hope this helped :)