Answer:
The horizontal component of the truck's velocity is: 23.70 m/s
The vertical component of the truck's velocity is: 3.13 m/s
Explanation:
You have to apply trigonometric identities for a right triangle (because the ramp can be seen as a right triangle where the speed is the hypotenuse), in order to obtain the components of the velocity vector.
The identities are:
Cosα= ![\frac{CA}{H}](https://tex.z-dn.net/?f=%5Cfrac%7BCA%7D%7BH%7D)
Senα= ![\frac{CO}{H}](https://tex.z-dn.net/?f=%5Cfrac%7BCO%7D%7BH%7D)
Where H is the hypotenuse, α is the angle, CA is the adjacent cathetus and CO is the opposite cathetus
The horizontal component of the truck's velocity is:
Let Vx represent it.
In this case, CA=Vx, H=24 and α=7.5 degrees
Vx=(24)Cos(7.5)
Vx=23.79 m/s
The vertical component of the truck's velocity is:
Let Vy represent it.
In this case, CO=Vy, H=24 and α=7.5 degrees
Vy=(24)Sen(7.5)
Vy=3.13 m/s
Answer:
≈20.9 km/hr
Explanation:
Average speed is the distance divided by time.
The train travels 50 km in 3 hours, then 96 km in 4 hours. So overall, the train travels 146 km in 7 hours. The average speed is:
146 km / 7 hr ≈ 20.9 km/hr
Not the answer but the answer will nit be B. hope yall find the answer